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Help me. simple question

  • 21-08-2014 5:35pm
    #1
    corglass
    Registered Users, Registered Users 2 Posts: 1,113 ✭✭✭


    Hey folks,

    Can someone please help me with part A in the question attached?

    Thanks a million


Comments

  • #2
    heavydemon
    Registered Users, Registered Users 2 Posts: 30 ✭heavydemon


    corglass wrote: »
    Hey folks,

    Can someone please help me with part A in the question attached?

    Thanks a million

    The answer is 3x
    simples


  • #3
    corglass
    Registered Users, Registered Users 2 Posts: 1,113 ✭✭✭corglass


    heavydemon wrote: »
    The answer is 3x
    simples

    It's clearly not. I don't know why you bothered to post that.


  • #4
    heavydemon
    Registered Users, Registered Users 2 Posts: 30 ✭heavydemon


    corglass wrote: »
    It's clearly not. I don't know why you bothered to post that.

    Im bored sorry


  • #5
    corglass
    Registered Users, Registered Users 2 Posts: 1,113 ✭✭✭corglass


    heavydemon wrote: »
    Im bored sorry

    Fair enough I guess. Anyone able to give me a steer?


  • #6
    corglass
    Registered Users, Registered Users 2 Posts: 1,113 ✭✭✭corglass


    corglass wrote: »
    Fair enough I guess. Anyone able to give me a steer?

    Anyone?


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  • #7
    Kavrocks
    Registered Users, Registered Users 2 Posts: 2,345 ✭✭✭Kavrocks


    corglass wrote: »
    Fair enough I guess. Anyone able to give me a steer?
    Convert the [LATEX]\sqrt{}[/LATEX] to a power and then you should see that you can apply the chain and product rules and finally evaluate it at x = 0.


  • #8
    Ompala
    Registered Users, Registered Users 2 Posts: 906 ✭✭✭Ompala


    corglass wrote: »
    Anyone?

    Square both sides, apply (implicit?) differentiation on the L.H.S and product rule on R.H.S, sub in for x=0 and should work


  • #9
    Chickentown
    Registered Users, Registered Users 2 Posts: 252 ✭✭Chickentown


    Get rid of the square root sign by raising the argument of the square root to 1/2.

    Now differentiate by chain rule. You will need to use the product rule while doing this.


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