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Integration question

  • 31-05-2014 9:01pm
    #1
    Pidge96
    Registered Users, Registered Users 2 Posts: 40 ✭


    How do you integrate something like this?

    (sin3xcos2x) dx,
    between pi over 2 and 0, 0 being the figure on the bottom of the integration sign?

    Sorry if this is basic but it's wrecking my head :)


Comments

  • #2
    sponsoredwalk
    Registered Users, Registered Users 2 Posts: 3,038 ✭✭✭sponsoredwalk


    One way would be to use the trigonometric product-to-sum formulas, as in this video:

    https://www.youtube.com/watch?v=FrNOfR8EX-I


  • #3
    Carawaystick
    Registered Users, Registered Users 2 Posts: 8,779 ✭✭✭Carawaystick


    I'm unsure of the answer, but the integral is "from 0 to pi/2"
    you always integrate from the lower figure on the integration sign to the upper one


  • #4
    TheBody
    Registered Users, Registered Users 2 Posts: 5,633 ✭✭✭TheBody


    Carawaystick wrote: »
    I'm unsure of the answer, but the integral is "from 0 to pi/2"
    you always integrate from the lower figure on the integration sign to the upper one

    In general, this is NOT true. It's just happens to be the case that most times it is usually set up this way.


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