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when logs of different base are on different sides of the =

FiachDubh · 2014-02-08 15:03:14

log4 (3x+1) = log2 (x-1) Do you do the log2 over log4 thing? Thanks

08-02-2014 3:03pm

#1

FiachDubh

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Posts: 61

log4 (3x+1) = log2 (x-1)

Do you do the log2 over log4 thing?
Thanks

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Comments

#2 08-02-2014 7:58pm

platypus

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Use change of base law to change log4(3x+1) to log2(3x+1)/log2(4) and you should be able to work on from there

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