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Help with an interest Rate Question

  • 14-11-2013 3:39pm
    #1
    Closed Accounts Posts: 1,102 ✭✭✭


    Hey,

    Im hoping someone can help me out.

    I have an AER of 10.38%

    I need to find the nominal interest rate if I were to compound monthly.

    So for example if I compound quarterly the nominal rate would be 10%.
    (1+0.1/4)^12 = 1.1038 - 1 = .1038 (the AER) with the 0.1 being the nominal rate.

    So I need to find X:

    (1+X/12)^12=1.1038?

    But how do


Comments

  • Moderators, Science, Health & Environment Moderators Posts: 1,852 Mod ✭✭✭✭Michael Collins


    Try taking the log (to any base you like) of both sides. The exponent of 12 will turn into a multiplicative factor on the left-hand side.


  • Closed Accounts Posts: 1,102 ✭✭✭DylanII


    Hey, thanks for your help :)

    I figured it out, so I thought Id post it incase anyone else is ever looking for something similar.

    What I done was:

    AER = 0.1038

    (1+r/12)^12 = AER + 1

    (1+r/12)^12 = 1.103812891 both sides of the equation to the power of 1/12

    (1+r/12) = 1.0082648 then multiply both sides by 12

    (12+r) = 12.0991776
    r= 12.0991776 - 12
    r= .0991776
    R = 9.91776%


  • Moderators, Science, Health & Environment Moderators Posts: 1,852 Mod ✭✭✭✭Michael Collins


    Yep, that's the way to do it. Taking the log would be no help at all, I wasn't thinking when I posted the above! Sorry!


  • Closed Accounts Posts: 1,102 ✭✭✭DylanII


    Yep, that's the way to do it. Taking the log would be no help at all, I wasn't thinking when I posted the above! Sorry!

    Thanks anyway :)

    Im not the best at math so I just assumed that you had another way of doing it :P


  • Registered Users, Registered Users 2 Posts: 5,141 ✭✭✭Yakuza


    Fair play for sorting it out, here's what I'd have done to make the calcs a little quicker:
    You arrived at:
    (1+r/12) = 1.0082648
    If you subtract 1 from both sides, you get :
    r/12 = .0082648 , now multiply both sides by 12 and you get :
    r= 0.0991776

    Powers / roots are the easiest way to solve such equations


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