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Drawing force digram

  • 13-11-2013 7:51am
    #1
    Hedgecutter
    Registered Users, Registered Users 2 Posts: 1,057 ✭✭✭


    I have to complete a force diagram from the image I have inserted, I have managed to draw the first joint but I am stuck on the second joint.

    What's puzzling me is the force of the Joint C-H, I have solved the force in A-C to be 14.14KN so can I take it C-H is the same force of 14.14kN.

    If I draw a line f-g through g parallel to the space diagram on the force diagram, Do I measure 14.14 to find F or do I need to draw c-f to find where f is?


Comments

  • #2
    Morbert
    Registered Users, Registered Users 2 Posts: 3,457 ✭✭✭Morbert


    Hedgecutter wrote: »
    I have to complete a force diagram from the image I have inserted, I have managed to draw the first joint but I am stuck on the second joint.

    What's puzzling me is the force of the Joint C-H, I have solved the force in A-C to be 14.14KN so can I take it C-H is the same force of 14.14kN.

    If I draw a line f-g through g parallel to the space diagram on the force diagram, Do I measure 14.14 to find F or do I need to draw c-f to find where f is?

    is the structure stationary? What is the object at joint D-H?


  • #3
    Hedgecutter
    Registered Users, Registered Users 2 Posts: 1,057 ✭✭✭Hedgecutter


    Morbert wrote: »
    is the structure stationary? What is the object at joint D-H?

    Sorry Should have stated that. Pinned A-D and roller at D-H.
    I'm just not sure how to start the second joint, where is the force coming from?


  • #4
    Morbert
    Registered Users, Registered Users 2 Posts: 3,457 ✭✭✭Morbert


    I would get the other joints first. Can we assume the structure is symmetrical?


  • #5
    Hedgecutter
    Registered Users, Registered Users 2 Posts: 1,057 ✭✭✭Hedgecutter


    Morbert wrote: »
    I would get the other joints first. Can we assume the structure is symmetrical?

    That's what i am not it sure about, I am inclined to assume it is. What I can say is before I left the class we were told do joint 1 first then move to joint 2 an so on.

    You can draw F G alright but it's the force C F that has me stumped.


  • #6
    Morbert
    Registered Users, Registered Users 2 Posts: 3,457 ✭✭✭Morbert


    Ok, last question. Do we know the length of the lines? If we do, then I think I have a solution.


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  • #7
    Hedgecutter
    Registered Users, Registered Users 2 Posts: 1,057 ✭✭✭Hedgecutter


    Morbert wrote: »
    Ok, last question. Do we know the length of the lines? If we do, then I think I have a solution.

    No I don't think so. My understanding is the only measurement is the force at the joint. You draw that and to find F you need two lines to intersect.


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