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Maths Help for my Nephew, please help...

  • 02-11-2013 5:14pm
    #1
    EORaghallaigh
    Registered Users, Registered Users 2 Posts: 37 ✭


    Hey Maths Gurus,

    Any idea how to solve the following quadratic using the abc or pq formula, I'm getting -sqrt2 as the answer, but i'm unsure...

    x^2 +sqrt8x +4 = 2

    Any ideas?

    Thanks,
    E


Comments

  • #2
    TheBody
    Registered Users, Registered Users 2 Posts: 5,633 ✭✭✭TheBody


    EORaghallaigh wrote: »
    Hey Maths Gurus,

    Any idea how to solve the following quadratic using the abc or pq formula, I'm getting -sqrt2 as the answer, but i'm unsure...

    x^2 +sqrt8x +4 = 2

    Any ideas?

    Thanks,
    E

    [latex]-\sqrt{2}[/latex] is correct.


  • #3
    EORaghallaigh
    Registered Users, Registered Users 2 Posts: 37 ✭EORaghallaigh


    Thanks TheBody, was going mad there for a while doubting myself; you're a legend


  • #4
    TheBody
    Registered Users, Registered Users 2 Posts: 5,633 ✭✭✭TheBody


    EORaghallaigh wrote: »
    Thanks TheBody, was going mad there for a while doubting myself; you're a legend

    Guilty as charged! :P Glad I could help.


  • #5
    Yakuza
    Registered Users, Registered Users 2 Posts: 5,141 ✭✭✭Yakuza


    I initially read this as [latex]x^2 - \sqrt{8x} + 4 =2[/latex] which is a whole different ball game to [latex]x^2 - \sqrt{8}x + 4 = 2[/latex], (i.e. the coeffecient of x is [latex]-\sqrt{8}[/latex] as opposed to the equation not being a quadratic by virtue of having a term involving a square root of x).

    Assuming the latter is the problem being asked, then [latex]-\sqrt{2}[/latex] is indeed the solution.


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