Eigenfunction of the Schrodinger wave equation

Smythe

In the attachment, the question is shown in bold, and I've been able to produce the working out as shown.

However, the last line where the provided solution simply states, "From the definition of γ, all the x^2 terms cancel leaving..."

How do the x^2 terms cancel, and how is this last line arrived at?

Thanks

Morbert

Smythe wrote: »

In the attachment, the question is shown in bold, and I've been able to produce the working out as shown.

However, the last line where the provided solution simply states, "From the definition of γ, all the x^2 terms cancel leaving..."

How do the x^2 terms cancel, and how is this last line arrived at?

Thanks

After you remove the brackets and replace [latex]\gamma[/latex], the first term becomes
[latex]-\frac{1}{2}m\omega^2x^2[/latex]
which cancels with the third term.

Smythe

Morbert wrote: »

After you remove the brackets and replace [latex]\gamma[/latex], the first term becomes
[latex]-\frac{1}{2}m\omega^2x^2[/latex]
which cancels with the third term.

Thanks very much Morbert.