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  • 13-05-2013 9:20am
    #1
    Registered Users, Registered Users 2 Posts: 4,331 ✭✭✭


    Can someone solve this for me please? I know its not quantum physics but I'm getting conflicting answers from different solution sites and I want to make sure I have the right answer:


Comments

  • Registered Users, Registered Users 2 Posts: 5,141 ✭✭✭Yakuza


    Look up BOMDAS - Brackets, orders, multiplication, division, addition, subtraction

    Starting with [latex]\left(\frac{\frac{2}{3}+\frac{1}{2}}{\frac{2}{5}}\right) \times 2 - 6 \div 3[/latex]
    Express the fraction to be summed as a single fraction, the common divisor is 6. Also, [latex]6 \div 3[/latex] reduces to 2:

    We now have: [latex]\left(\frac{\frac{4}{6}+\frac{3}{6}}{\frac{2}5}}\right) \times 2 - 2[/latex]

    add the fractions:[latex]\left(\frac{\frac{7}{6}}{\frac{2}{5}}\right) \times 2 - 2[/latex]

    When dividing by a faction, turn it upside down and multiply:[latex]\left(\frac{7}{6} \times \frac{5}{2} \right) \times 2 - 2[/latex]

    Multiply out the factions, and bring in the multiplier of 2: [latex]\left(\frac{70}{12} \right) - 2[/latex]

    Simplify, and express the -2 in 6ths: [latex]\frac{35}{6} - \frac{12}{6}[/latex]

    Simplify again: [latex]\frac{23}{6}[/latex]


  • Registered Users, Registered Users 2 Posts: 4,331 ✭✭✭Keyzer


    Thanks - that's the answer I had but some of the online calculators are giving me conflicting answers.


  • Registered Users, Registered Users 2 Posts: 5,141 ✭✭✭Yakuza


    Some of those calculators are very sensitive to how you input the problem, sometimes the best way is pen and paper :)


  • Registered Users, Registered Users 2 Posts: 4,331 ✭✭✭Keyzer


    one more for you, just to humour me...


  • Registered Users, Registered Users 2 Posts: 5,143 ✭✭✭locum-motion


    Keyzer wrote: »
    one more for you, just to humour me...

    I got that one as far as 5,339 / 4,680

    I'm sure that it could be simplified further by finding the highest common factor of 5,339 and 4,680.

    But I'm not gonna try.

    Other than brute-forcing it in Excel or some other 'trial-and-error' method, how do you find a HCF?


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  • Registered Users, Registered Users 2 Posts: 5,141 ✭✭✭Yakuza


    Keyzer wrote: »
    one more for you, just to humour me...

    Post your answer, and I'll see if I get the same one. Express the 31/5 - 5/8 as fortieths and the 5/4 and 4/6 as twelfths and continue from there.

    Edit: I got a slightly different numerator to locum-motion, the same denominator.


  • Registered Users, Registered Users 2 Posts: 4,331 ✭✭✭Keyzer


    5359 / 4680


  • Registered Users, Registered Users 2 Posts: 5,141 ✭✭✭Yakuza


    That's what I got too, for what it's worth :)


  • Registered Users, Registered Users 2 Posts: 4,331 ✭✭✭Keyzer


    Thank you, bloody pain in the neck that I can't get the answers from past exam papers from the lecturer.


  • Registered Users, Registered Users 2 Posts: 5,143 ✭✭✭locum-motion


    ... 5,339 / 4,680
    ...
    Yakuza wrote: »
    ... I got a slightly different numerator to locum-motion, the same denominator.
    Keyzer wrote: »
    5359 / 4680


    Actually, I've just been to the bin to dig out the envelope I worked on the back of.
    I got 5,359 too. I just typed it wrong!


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  • Registered Users, Registered Users 2 Posts: 5,143 ✭✭✭locum-motion


    ...
    I'm sure that it could be simplified further by finding the highest common factor of 5,339 and 4,680...

    Should I have said "lowest common denominator" there, not HCF?


  • Registered Users, Registered Users 2 Posts: 939 ✭✭✭Ciaran


    Other than brute-forcing it in Excel or some other 'trial-and-error' method, how do you find a HCF?
    Break each number down to its prime factors and see which ones are common to both numbers.


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