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Led circuit problem

  • 24-01-2013 5:37pm
    #1
    Registered Users, Registered Users 2 Posts: 58 ✭✭


    Hi guys,

    Hope ye can help? I am a complete noob in terms of circuits so any advice is greatly appreciated. I wired a single led with push to make switch a while ago but need help on this one.

    I have 3 different colour LED's and 3 push to make switches that i want to connect to a 9V battery inside a small box. Two of the LED's have a 3.4V forward drop and the other is 2.4V with a Max current of 20mA. Should i wire them in series or parallel? Only one LED will be active at any one time so wondering which way is better.

    Also how does one calculate resistance for this circuit?

    If i have left anything out i apologize, but any help is appreciated. Thank you.


Comments

  • Closed Accounts Posts: 270 ✭✭Bejubby


    I think its best to wire in paralell
    Use ohms law for calculations:v is voltage,I is current,r is resistance

    V
    --
    I*r

    Cover the letter your looking for and work out the formula.

    Forget that its for series


    Paralell you need to wire up the circuit
    Then get your mrasurments and we'll use a different formula


  • Registered Users, Registered Users 2 Posts: 58 ✭✭customPC


    Wouldn't it be better to have all the values and understand it before actually wiring


  • Registered Users, Registered Users 2 Posts: 2,320 ✭✭✭Chet T16


    Are you sure all the LED's have the same forward drop? Different colours normally have different drops


  • Registered Users, Registered Users 2 Posts: 58 ✭✭customPC


    Just double checked there Chet and you are correct sorry. 2 of them have 3.4V drop and the other has 2.4V drop


  • Registered Users, Registered Users 2 Posts: 2,320 ✭✭✭Chet T16


    Connect them like this

    237874.PNG

    You need to calculate the value for each resistor individually taking the voltage as (Battery Voltage - Diode Drop) and 20mA as your current


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  • Registered Users, Registered Users 2 Posts: 58 ✭✭customPC


    Thanks Chet. Thats a great help. Now to put my soldering to the test:-)


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