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JC project maths Q

skylover · 2013-01-12 14:11:59

Using the Text and Tests supplement book and just having difficulty with one question. Page 26-Q6 To convert 20kg to pounds using the equation found (11x-5y=0) According to question Kg on y axis so therefore y value in equation? so subbing in 20 for y gives 11x- 5(20)=0 x=9.09 lb, which is not correct? All help much…

12-01-2013 2:11pm

#1

skylover

Registered Users, Registered Users 2 Posts: 1 ✭

Join Date: August 2012

Posts: 0

Using the Text and Tests supplement book and just having difficulty with one question.

Page 26-Q6
To convert 20kg to pounds using the equation found (11x-5y=0)
According to question Kg on y axis so therefore y value in equation?
so subbing in 20 for y gives
11x- 5(20)=0
x=9.09 lb, which is not correct?

All help much appreciated.

0

Comments

#2 30-01-2013 9:53pm

Uqw9hOq7

Registered Users, Registered Users 2 Posts: 4 ✭

Join Date: January 2013

Posts: 4

Well, to convert KG into lb, I just multiply by 2,2.

But for that method:
11x - 5y = 0
11(20) - 5y = 0
220 - 5y = 0
5y = 220
y = 220/5
y = 44

0