Determining initial velocity of an electron

Smythe

Consider an electron that has its position measured to within a nuclear radius in a laboratory. What is the uncertainty in its position uncertainty one day later?

What equation should I use to determine the initial velocity of the electron?

I believe this would be the first thing I should determine in order to answer the question.

Thanks!

Smythe

I have used:

ΔxΔ(mv) = h/2Pi

(10^-14) (9.1 x 10^-31) (Δv) = h/2Pi

Δv = 1.16 x 10^10 m/s

Am I going about this the right way?

What way do I go now about solving the original question?

Do I simply multiply the answer for Δv by (3600x24) i.e. the number of seconds in a day?

If I do this I get an answer of Δx = 1.00 x 10^15 m

Thanks

Smythe

Should I instead be using the relativistic equation to find the uncertainty in the momentum, and not p=mv as I done above?

Smythe

Here is a similar question:
Specifically the *2nd* example
http://www.people.vcu.edu/~rgowdy/mod/122/xmp4.htm

The solution does not appear to have used the relativistic equation.

Should my solution simply be the same but substituting their time (they have one year (3.15x10^7)) with my time (one day)?

krd

Where are you getting these questions?

Is it homework or exam papers?

Post the exam papers, I'd like a look.