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Nuclear Radius Equation R = R0 A^(1/3)

Smythe · 2012-10-06 15:50:59

If using the nuclear radius equation: R = R0 A^(1/3) as shown half-way down this page: http://en.wikipedia.org/wiki/Atomic_nucleus r0 = 1.25 fm = 1.25 × 10−15 m Is this value for r0 always this value, irrespective of the material in question? For example, if it was gold, or some other material? Thanks

06-10-2012 04:50PM

#1

Smythe

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If using the nuclear radius equation:

R = R0 A^(1/3)

as shown half-way down this page:
http://en.wikipedia.org/wiki/Atomic_nucleus

r0 = 1.25 fm = 1.25 × 10−15 m

Is this value for r0 always this value, irrespective of the material in question? For example, if it was gold, or some other material?

Thanks

0

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#2 06-10-2012 11:30PM

Capt'n Midnight

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http://www.physicsforums.com/showthread.php?p=4103195

Approximately. That equation is true for any substance of constant density. That's a pretty good assumption for cold nuclear matter.

In this equation, the constant r0 varies by 0.2 fm, depending on the nucleus in question, but this is less than 20% change from a constant
is what it says on that wiki page

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