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Nuclear Radius Equation R = R0 A^(1/3)

  • 06-10-2012 03:50PM
    #1
    Smythe
    Registered Users, Registered Users 2 Posts: 434 ✭✭


    If using the nuclear radius equation:

    R = R0 A^(1/3)

    as shown half-way down this page:
    http://en.wikipedia.org/wiki/Atomic_nucleus

    r0 = 1.25 fm = 1.25 × 10−15 m

    Is this value for r0 always this value, irrespective of the material in question? For example, if it was gold, or some other material?

    Thanks


Comments

  • #2
    Capt'n Midnight
    Moderators, Recreation & Hobbies Moderators, Science, Health & Environment Moderators, Technology & Internet Moderators Posts: 94,366 Mod ✭✭✭✭Capt'n Midnight


    http://www.physicsforums.com/showthread.php?p=4103195
    Approximately. That equation is true for any substance of constant density. That's a pretty good assumption for cold nuclear matter.

    In this equation, the constant r0 varies by 0.2 fm, depending on the nucleus in question, but this is less than 20% change from a constant
    is what it says on that wiki page


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