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maths problem??

  • 25-09-2012 7:32pm
    #1
    mkelly1992
    Registered Users, Registered Users 2 Posts: 11 ✭


    Use factoring to solve the polynomial equation: 2X^3+4x^2-48x=0?
    can't seem to get the right answer, it isn't x=0,x=-6, x=4. or 2x(x+6)(x-4)=0


Comments

  • #2
    brophya2007
    Registered Users, Registered Users 2 Posts: 298 ✭✭brophya2007


    That looks right to me


  • #3
    mkelly1992
    Registered Users, Registered Users 2 Posts: 11 ✭mkelly1992


    hmm... thought so too, maybe the answer key is wrong


  • #4
    joeKel73
    Closed Accounts Posts: 3,689 ✭✭✭joeKel73


    Solution looks valid. What the "answer key"?


  • #5
    Ficheall
    Registered Users, Registered Users 2 Posts: 9,034 ✭✭✭Ficheall


    Is this an online thing? They can be fierce pernickety about how you write your answers, and often mark the correct solution as incorrect. Is there some provision for writing different satisfactory solutions, or is there just one answer box?


  • #6
    ispini1984
    Closed Accounts Posts: 241 ✭✭ispini1984


    is the equation 2*(x^3) + 4*(x^2) - 48x = 0

    ie 2times Xcubed PLUS 4times Xsquared MINUS 48timesX EQUALS 0

    If so, I have worked it out to be X = 4


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  • #7
    Ficheall
    Registered Users, Registered Users 2 Posts: 9,034 ✭✭✭Ficheall


    ispini1984 wrote: »
    is the equation 2*(x^3) + 4*(x^2) - 48x = 0

    ie 2times Xcubed PLUS 4times Xsquared MINUS 48timesX EQUALS 0

    If so, I have worked it out to be X = 4
    What about x=0?


  • #8
    ispini1984
    Closed Accounts Posts: 241 ✭✭ispini1984


    Ficheall wrote: »
    What about x=0?


    I dont like 0 as an answer :D:D:D


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