Advertisement
If you have a new account but are having problems posting or verifying your account, please email us on hello@boards.ie for help. Thanks :)
Hello all! Please ensure that you are posting a new thread or question in the appropriate forum. The Feedback forum is overwhelmed with questions that are having to be moved elsewhere. If you need help to verify your account contact hello@boards.ie
Hi there,
There is an issue with role permissions that is being worked on at the moment.
If you are having trouble with access or permissions on regional forums please post here to get access: https://www.boards.ie/discussion/2058365403/you-do-not-have-permission-for-that#latest

Wavelength for an electron

  • 25-09-2012 5:16pm
    #1
    Registered Users, Registered Users 2 Posts: 434 ✭✭


    I'm trying to work out the wavelength of an electron with a kinetic energy of 1keV

    So I intend on using
    de Broglie wavelength λ = h/p

    and

    Relativistic mass equation
    E^2 = p^2 c^2 + (m0)^2 c^4

    then inputting the rest mass energy of an electron (511 keV) into the formula above. Though do I need to convert this first to kg?

    Also, I'd still be left with two unknowns in mass eqn i.e. E and p, so how do I obtain the value for E?

    Or am I going about this the wrong way?

    Thank you.


Comments

  • Registered Users, Registered Users 2 Posts: 147 ✭✭citrus burst


    Smythe wrote: »
    I'm trying to work out the wavelength of an electron with a kinetic energy of 1keV

    So I intend on using
    de Broglie wavelength λ = h/p

    and

    Relativistic mass equation
    E^2 = p^2 c^2 + (m0)^2 c^4

    then inputting the rest mass energy of an electron (511 keV) into the formula above. Though do I need to convert this first to kg?

    Also, I'd still be left with two unknowns in mass eqn i.e. E and p, so how do I obtain the value for E?

    Or am I going about this the wrong way?

    Thank you.

    You are going about this alright, but there is a much easier formula that you can use.

    λ = h/(mv) . (1 - v^2/c^2)^1/2

    This is basically the formula you would have worked out if you had have followed through with what you were doing, although it is tricky enough.

    The only unknown you have now is v, which you get by using

    E = (1/2) m v^2
    => v =(2E/m)^1/2

    Also you are given the energy of the system E. Its 1 keV


  • Registered Users, Registered Users 2 Posts: 434 ✭✭Smythe


    Thanks very much for that citrus burst.


Advertisement