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Quadratic equations, not a clue

  • 23-09-2012 6:04pm
    #1
    Registered Users, Registered Users 2 Posts: 3,651 ✭✭✭Captain Slow IRL


    Is there any good online guides to understanding these, I'm looking at some exercises and I can't make head or tail to working them out.


Comments

  • Registered Users, Registered Users 2 Posts: 179 ✭✭Neodymium




  • Registered Users, Registered Users 2 Posts: 5,633 ✭✭✭TheBody


    What sort of problems are you having op? Are you having problems factorising them or solving them or both?

    Maybe check out this to get you started:

    http://www.youtube.com/watch?v=SDe-1lGeS0U


  • Registered Users, Registered Users 2 Posts: 3,651 ✭✭✭Captain Slow IRL


    I got some notes off a lecturer and couldn't understand them, I was missing the last few days so didn't get a more in-depth explanation of the notes.

    Thanks for the links, I was looking at Khan academy before but must have been looking in the wrong section :o


  • Registered Users, Registered Users 2 Posts: 5,633 ✭✭✭TheBody


    If you get stuck on any bit, lash it up here and somebody will be along to help you out.


  • Registered Users, Registered Users 2 Posts: 103 ✭✭Jan Hus


    Quadratic are not majorly tricky - try the quadratic formula if you are finding it hard going.


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  • Registered Users, Registered Users 2 Posts: 3,651 ✭✭✭Captain Slow IRL


    What exactly is a quatratic formula? Is that the big X?

    I was missing from the first week of college (due to unavoidable events) and missed out on a coupel of classes. Having 2 classes since, spending a lot of time working off the notes and doing some exercises has helped me a lot.

    Thanks for all the links and replies, they've helped me a lot - I'm over 14 years out of school and this stuff was like chinese to me!


  • Registered Users, Registered Users 2 Posts: 5,633 ✭✭✭TheBody


    What exactly is a quatratic formula? Is that the big X?

    I was missing from the first week of college (due to unavoidable events) and missed out on a coupel of classes. Having 2 classes since, spending a lot of time working off the notes and doing some exercises has helped me a lot.

    Thanks for all the links and replies, they've helped me a lot - I'm over 14 years out of school and this stuff was like chinese to me!

    The poster was referring to the formula for solving quadratic equations. It is useful at times but is a bit slow if it can be factored using brackets.

    See here for the formula:
    http://en.wikipedia.org/wiki/Quadratic_equation


  • Registered Users, Registered Users 2 Posts: 3,651 ✭✭✭Captain Slow IRL


    Can someone solve this?!

    5x - y + 2z = 25
    3x + 2y - 3z = 16
    2x - y + z = 9


  • Registered Users, Registered Users 2 Posts: 5,633 ✭✭✭TheBody


    Can someone solve this?!

    5x - y + 2z = 25
    3x + 2y - 3z = 16
    2x - x + z = 9

    Is that a typo in the last equation? I presume you mean 2x-y+z=9 ?

    Also, are you using matrices or just simultaneous equations method to solve the system?


  • Posts: 0 CMod ✭✭✭✭ Kenzie Big Watchdog


    That's not quadratic equations, that's simultaneous / system of equations
    (assuming you don't use matrices)

    take a pair of equations and multiply one equation so that one of the variables cancels out with the variable in the other equation of the pair

    e.g. if you have 4x + 2y + z = 10
    and 5x + 2y + 3z = 4

    then multiply the first equation by -1 to cancel out the Ys
    so it changes to -4x - 2y - z = -10
    then stick the other one underneath and add them up

    - 4x - 2y - z = -10
    5x + 2y + 3z= 4

    that leaves you with (-4 + 5)x +(3-1)z = (-10+4)
    => x +2z = -6

    do the same with a different pair of the equations, if you've used equation a and b, try using b and c to again cancel out the same variable
    mix the result with the result above to solve for one variable
    http://www.sparknotes.com/math/algebra2/systemsofthreeequations/section1.rhtml


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