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Applied Maths

  • 19-09-2012 7:43pm
    #1
    Troxck
    Closed Accounts Posts: 1,386 ✭✭✭


    Okay so I'm in TY and this year we have the option of doing Applied Maths, and it's going okay, except for one question, I just can't get it and it's my only one left. Anyway, the question is

    a car has a maximum deceleration of 4 m/s squared. Find it’s minimum stopping time distance if it’s traveling at 8m/s.

    Could you also explain how you got the answer? I feel awful but I'm really stumped on this one even though I know it's simple


Comments

  • #2
    decisions
    Closed Accounts Posts: 8,207 ✭✭✭decisions


    u = 8
    v = 0
    a = -4
    s = ?

    v^2 = u^2 + 2as

    Should do it.


  • #3
    Troxck
    Closed Accounts Posts: 1,386 ✭✭✭Troxck


    decisions wrote: »
    u = 8
    v = 0
    a = -4
    s = ?

    v^2 = u^2 + 2as

    Should do it.

    Thank you so much. I put 4 not minus 4.
    Again, thanks a million!


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