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probabilty

  • 24-05-2012 1:47pm
    #1
    GoodThing007
    Registered Users, Registered Users 2 Posts: 3 ✭


    A simple probablity question, but its just slipped my mind!

    The life expectancy of three men A, B and C over a 20 year period depends on their age and
    is given by:
    p(A) = 4/15
    p(B) = 11/15
    p(C) =14/15
    .
    Determine the probability that in 20 years:
    (i) All 3 men will be alive
    (ii) A will be alive and B and C will be dead
    (iii) All three will be dead.
    (iv) At least one man will be alive.


    Can somebody please show me how part (iv) is worked out?

    Any help would be greatly appreciated!


Comments

  • #2
    Neodymium
    Registered Users, Registered Users 2 Posts: 179 ✭✭Neodymium


    the answer for part iv is 1 - (iii) answer.

    1 - (11/15)(4/15)(1/15) = 3331/3375


  • #3
    GoodThing007
    Registered Users, Registered Users 2 Posts: 3 ✭GoodThing007


    Thanks!


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