Bit of shell script loop help please.

Sebzy

I'm trying to write a script to reset the ownership on users home directory's

Problem
drwx

---

12 root rootg 408 Feb 21 17:24 blogsj1

What I'm trying to achieve
drwxr-xr-x 12 blogsj1 Subgroup1 408 Feb 21 17:24 blogsj1

Have a directory structure that looks like this

Group1
- SubGroup1
- - blogsj1
- - blogsj2
- SubGroup2
- - blogsj3
- - blogsj4
Group2
- SubGroup3
- - blogsj1
etc.....

So far I've figured out how to get a list of each users directory

#!/bin/sh
for file in ./*/*/*; do
if [ -d $file ]; then
echo $file;
fi
done

Now I'm stuck
How do I use that $file which shows "./Group1/SubGroup1/blogsj1" into separate variables such as

$groupname
$subgroupname
$username

I can guess the rest (I think)

Thanks

Sebzy

OSI wrote: »

You could use awk to get the various parts of the string using / as a delimiter

eg:

echo "/var/log/httpd" | awk -F/ '{print $2}'

Would print out var

Thanks but figured out a slightly different method.

#!/bin/bash
for file in ./*/*/*; do
   if [ -d $file ]; then
        group=`echo $file | cut -d/ -f2`;
        subgroup=`echo $file | cut -d/ -f3`;
        user=`echo $file | cut -d/ -f4`;
        echo $file;
        echo "Group : $group";
        echo "SubGroup : $subgroup";
        echo "User : $user";
        exit
   fi
done

On to the next step....

schrodinger

Example:

[schrodinger@purplehaze (13:01) ~/tmp/boards] $ mkdir -p group{1..3}/subgroup{1..3}/blog1
[schrodinger@purplehaze (13:01) ~/tmp/boards] $ find ./*/*/*/ -type d | awk -F/ '{print $4 ":" $3 " " $0;} | xargs -n 2 chown
[schrodinger@purplehaze (13:01) ~/tmp/boards] $ 

croo

for file in `find /path -type d -print`
do
echo $file
done

will list all directories from the point path
replace path with home or the user's home
then replace the echo with an appropriate chmod command
and you should be good.

Note the ` surround the find are backquotes (left of the 1 on my keyboard), not '