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Lorentz factor for particle moving at angle

Smythe · 2011-10-15 20:28:35

I noticed on this webpage; http://www.relativitycalculator.com/addition_relativistic_velocities.shtml near the very bottom there is a section entitled, "What, therefore, would r & θ appear to be to an observor in relatively moving S'?" Example 1, the formula then states: tanθ' = u'y / u'x I understand why they're doing…

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15-10-2011 9:28pm

#1

Smythe

Registered Users Posts: 434 ✭✭

Join Date: March 2010

Posts: 232

I noticed on this webpage;
http://www.relativitycalculator.com/addition_relativistic_velocities.shtml

near the very bottom there is a section entitled, "What, therefore, would r & θ appear to be to an observor in relatively moving S'?"

Example 1, the formula then states:

tanθ' = u'y / u'x I understand why they're doing this.

Though after this, can anyone explain the next part of the progression?

Why have they applied a γ to the denominator of u'y but not to u'x ?

Thank you

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#2 17-10-2011 1:47pm
Morbert

Registered Users Posts: 3,457 ✭✭✭

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Posts: 3397

Look at the section: "Relativistic Velocity Transformation Equations: A Summary"

Notice the difference in form between ux and uy.

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