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How was x eliminated from this equation?

Smythe · 2011-10-01 17:48:55

At the bottom of this page: http://www.cv.nrao.edu/course/astr534/LorentzTransform.html It states; Lorentz factor: How did they eliminate x? I tried substituting the stated x value into the equation for x', but didn't get anywhere.

01-10-2011 5:48pm

#1

Smythe

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At the bottom of this page:
http://www.cv.nrao.edu/course/astr534/LorentzTransform.html

It states;
Lorentz factor:

x=(x+vt) and x=(x−vt)

Eliminating x from this pair of equations yields
t=(t+vxc2)

How did they eliminate x?

I tried substituting the stated x value into the equation for x', but didn't get anywhere.

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Comments

#2 01-10-2011 7:06pm

Fremen

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Looks to me like that should work (though I haven't done it... can't find a pen).

You should get a gamma-squared term when you do the substitution, so you'll need to square both sides of the lorentz factor equation and sub that in too.

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