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Gamsat Practice Paper 2 Question 108?

  • 07-07-2011 6:48pm
    #1
    spotsanddots
    Registered Users, Registered Users 2 Posts: 132 ✭✭


    Anyone know how to approach this one?


Comments

  • #2
    spagboll
    Closed Accounts Posts: 283 ✭✭spagboll


    post it, i don't have the booklets any more, we can delete after we solve it


  • #3
    etymon
    Closed Accounts Posts: 467 ✭✭etymon


    Screen shot 2011-07-11 at 20.47.02.png

    is it that one?


  • #4
    spagboll
    Closed Accounts Posts: 283 ✭✭spagboll


    reflex answer, option A


  • #5
    etymon
    Closed Accounts Posts: 467 ✭✭etymon


    well I certainly haven't a clue

    (so I'd pick C :D)


  • #6
    Yillan
    Registered Users, Registered Users 2 Posts: 932 ✭✭✭Yillan


    Well there is no info given about machine frequencies or televisions, so you can rule C and D out immediately. A says that frequencies above 4500 are not heard by humans which is a contradiction of the info in the passage (to 5000).

    B is true and contains info given to you in the passage.

    Edit: Man I wish I was preparing for the GAMSAT again... :)


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  • #7
    Bonnieaurstomp
    Registered Users, Registered Users 2 Posts: 24 ✭Bonnieaurstomp


    Ok we have answers to two different questions now. It's seriously disturbing how quickly you forget this stuff.

    In answer to the question relating to efffusion of gases, I think it's a simple case of plugging in the numbers once you have the correct answer to the previous question.

    Graham's law would have the rate of effusion in relation to density as answer D, but I think you have to switch the answer upside down because it states that it is inversely proportional for time.

    I distinctly remember getting 107 wrong and the subsequent question wrong as a result.

    Once you have the right answer for 107 plugging the figures in you get

    250/100=The square of x/The square of 40 which gives an answer of 250.

    If I'm completely wrong I hang my head in shame and give back my 75 in section 3. I'm definitely gonna be wrong, and boy do I not miss this stuff.


  • #8
    bubbleking
    Closed Accounts Posts: 1,143 ✭✭✭bubbleking


    I havnt a fcuking clue! how I got by the GAMSAT I'll never know. I hope that doesnt come up in med school :o


  • #9
    del85
    Registered Users, Registered Users 2 Posts: 129 ✭✭del85


    spotsanddots wrote: »
    Anyone know how to approach this one?

    I can't even bring myself to click on the link :o


  • #10
    spotsanddots
    Registered Users, Registered Users 2 Posts: 132 ✭✭spotsanddots


    the question is the very last unit in practice paper 2


  • #11
    Annaroberts22
    Closed Accounts Posts: 29 ✭Annaroberts22


    We are expected to recall the main equation for Graham's law for this question which is

    R1/R2 = SQR M2/ SQR M1

    SQR= square root of

    so you work out the rate of effusion (R1) for argon which is 1/100 and for the unknown gas which is 1/250 (R2). M is the molecular/atomic/molar mass based on what is given. in this case atomic mass and molar mass of argon are the same as 40. You then just put the numbers into the equation to solve for M2 to give 250 as the molar mass of the unknown gas.

    This seems to work but I certainly didn't get it immediately and had to ask someone else's help who then came up with this. It does require knowing Graham's law off memory so bit naughty on GAMSAT's behalf :-(

    However, can we also get to this equation by combining the two equations given in the question?? I'm not sure about this.


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