Advertisement
If you have a new account but are having problems posting or verifying your account, please email us on hello@boards.ie for help. Thanks :)
Hello all! Please ensure that you are posting a new thread or question in the appropriate forum. The Feedback forum is overwhelmed with questions that are having to be moved elsewhere. If you need help to verify your account contact hello@boards.ie
Hi there,
There is an issue with role permissions that is being worked on at the moment.
If you are having trouble with access or permissions on regional forums please post here to get access: https://www.boards.ie/discussion/2058365403/you-do-not-have-permission-for-that#latest

The line - higher math problem

  • 11-05-2011 4:54pm
    #1
    Closed Accounts Posts: 147 ✭✭


    the lenght of the perpendicular to a line from the origin is 5 units . the line passes through the point (3,5) . Find the equations of two such lines.


    how to ?


Comments

  • Registered Users, Registered Users 2 Posts: 47 ShonyBoulders


    Well if it's a line from the origin...


  • Registered Users, Registered Users 2 Posts: 927 ✭✭✭Maybe_Memories


    Areq wrote: »
    the lenght of the perpendicular to a line from the origin is 5 units . the line passes through the point (3,5) . Find the equations of two such lines.


    how to ?

    Throw the info into your distance formula, get the slope of the line and the equation of the line, then use all that to get the perpendicular lines. you'll probably get x^2 and y^2 so that'll give you the two possibilities


  • Registered Users, Registered Users 2 Posts: 1,595 ✭✭✭MathsManiac


    Use the general form of the line: y = mx +c, and try to use the given conditions to find m and c, as follows:

    Sub. in the point (3, 5), and use that to write c in terms of m, so now you have the equation of the line in terms of m alone (and x and y, obviously).

    Then, use the formula for the distance from a point to a line to write a second equation. This should be in terms of m alone, and be of the form of a modulus divided a square root equal to a constant.

    Multiple across by the denominator, and square both sides and you'll have a quadratic in m. Should be ok from there.


Advertisement