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Quick Help with Maths Q

  • 23-02-2011 11:55am
    #1
    Registered Users, Registered Users 2 Posts: 838 ✭✭✭


    Not sure if this is the right place to post but This one sum has been doing my head in now for a good 45 minutes.I know it but I don't if that makes sense?!

    p { margin-bottom: 0.21cm; } Explain why i[FONT=Times New Roman, serif]³[/FONT][FONT=Times New Roman, serif] = -1. If [/FONT][FONT=Times New Roman, serif]w [/FONT][FONT=Times New Roman, serif]= 3[/FONT][FONT=Times New Roman, serif]i[/FONT][FONT=Times New Roman, serif], show that [/FONT][FONT=Times New Roman, serif]w[/FONT][FONT=Times New Roman, serif]³ –[/FONT][FONT=Times New Roman, serif] [/FONT][FONT=Times New Roman, serif][/FONT][FONT=Times New Roman, serif]+ 9[/FONT][FONT=Times New Roman, serif]w[/FONT][FONT=Times New Roman, serif] – 9 = 0[/FONT]


Comments

  • Registered Users, Registered Users 2 Posts: 88 ✭✭sparagon


    Ok well i= root minus one..so i sqaured is minus one
    And for the other just sub in w and multiply it out replacing i squared with minus one


  • Registered Users, Registered Users 2 Posts: 2,819 ✭✭✭EuropeanSon


    i^3 isn't -1, it's -i.


  • Registered Users, Registered Users 2 Posts: 88 ✭✭sparagon


    I never said it was.


  • Registered Users, Registered Users 2 Posts: 2,819 ✭✭✭EuropeanSon


    sparagon wrote: »
    I never said it was.

    That was directed at the OP.


  • Registered Users, Registered Users 2 Posts: 838 ✭✭✭Wats_in_a_name


    Turns out it was a mistake in the book. Should of read i³ = -i

    So I have that one sorted but now I'm stuck on.

    If x² = 9 Verify x = ± 3

    Could you just go
    -3 x -3 = 9
    3 x 3 = 9

    Then it goes on if | a + 3i | = 5 find the 2 possible values of a.

    I know it's ± 4 but how do I show that?

    Thanks for the help.


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  • Registered Users, Registered Users 2 Posts: 838 ✭✭✭Wats_in_a_name


    Never mind. Worked it out. I was trying to over think it!


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