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Total energy of the sun problem

  • 12-12-2010 9:38pm
    #1
    Closed Accounts Posts: 1,622 ✭✭✭


    I have to calculate the total energy output by the sun every second,

    The sun's temperature is given as 5770K
    its radius is 6.96x10^8m

    I decided to use Stephan Boltzmann's law but I don't know if I'm right

    I used J=AσT^4 where the A is the area of the sun 4πr^2, T is the absolute temperature and σ is Boltzmann's constant (1.38x10^-23)

    I got 8.08x10^8 Joules/sec, am I way off? I have looked but can't find a figure for it.


Comments

  • Registered Users, Registered Users 2 Posts: 1,576 ✭✭✭Improbable


    From wikipedia:

    The proton–proton chain occurs around 9.2×10^37 times each second in the core of the Sun. Since this reaction uses four free protons (hydrogen nuclei), it converts about 3.7 × 10^38 protons to alpha particles (helium nuclei) every second (out of a total of ~8.9 × 10^56 free protons in the Sun), or about 6.2 × 10^11 kg per second.[37] Since fusing hydrogen into helium releases around 0.7% of the fused mass as energy,[38] the Sun releases energy at the mass-energy conversion rate of 4.26 million metric tons per second, 384.6 yottawatts (3.846×10^26 W)


  • Registered Users, Registered Users 2 Posts: 2,892 ✭✭✭ChocolateSauce


    Improbable wrote: »
    From wikipedia:

    The proton–proton chain occurs around 9.2×10^37 times each second in the core of the Sun. Since this reaction uses four free protons (hydrogen nuclei), it converts about 3.7 × 10^38 protons to alpha particles (helium nuclei) every second (out of a total of ~8.9 × 10^56 free protons in the Sun), or about 6.2 × 10^11 kg per second.[37] Since fusing hydrogen into helium releases around 0.7% of the fused mass as energy,[38] the Sun releases energy at the mass-energy conversion rate of 4.26 million metric tons per second, 384.6 yottawatts (3.846×10^26 W)

    And that means that it emits millions of tonnes of light every second, which is awesome.
    :pac:


  • Registered Users, Registered Users 2 Posts: 267 ✭✭Tears in Rain


    I have to calculate the total energy output by the sun every second,

    The sun's temperature is given as 5770K
    its radius is 6.96x10^8m

    I decided to use Stephan Boltzmann's law but I don't know if I'm right

    I used J=AσT^4 where the A is the area of the sun 4πr^2, T is the absolute temperature and σ is Boltzmann's constant (1.38x10^-23)

    I got 8.08x10^8 Joules/sec, am I way off? I have looked but can't find a figure for it.

    You're using the wrong constant, you should be using the Stefan-Boltzmann constant instead of the Boltzmann constant.

    If you use the Stefan-Boltzman constant (value of roughly 5.67 * 10^-8 ) you get the correct answer...


  • Registered Users, Registered Users 2 Posts: 1,136 ✭✭✭del88


    Seen brian cox doing something similar in "wonders of the solar system"


  • Banned (with Prison Access) Posts: 1,380 ✭✭✭derry


    That video requred for me two looks to get what he was saying

    What a lot of watt the sun produces

    Derry


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