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can I use a s 110v without transformer/adapter.

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  • 01-12-2010 3:26pm
    #1
    foret
    Registered Users Posts: 69 ✭✭


    Product: Candle warmer , 110v , 20 watts power output.

    Q: can I use a s 110v without transformer/adapter.?

    If i wired to 3pin plug would it overheat/blow fuse. ? !

    Thanks.


Comments

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    #2
    Jonathan
    Moderators, Education Moderators, Home & Garden Moderators Posts: 8,105 Mod ✭✭✭✭Jonathan


    Yes. It will blow/overheat!

    Although check it because a lot of transformers will accept 110V - 240V.


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    #3
    Michael Collins
    Moderators, Science, Health & Environment Moderators Posts: 1,846 Mod ✭✭✭✭Michael Collins


    Jonathan wrote: »
    Yes.

    Although check it because a lot of transformers will accept 110V - 240V.

    So you want to use a 110 V device on 230 V supply, is that what you're asking?

    If so I think Jonathan means "Yes" as in, it will overheat or blow a fuse...as in DO NOT do it!


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    #4
    Jonathan
    Moderators, Education Moderators, Home & Garden Moderators Posts: 8,105 Mod ✭✭✭✭Jonathan


    Post edited. Didn't realise the ambiguity. :o


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    #5
    pieface_ie
    Closed Accounts Posts: 301 ✭✭pieface_ie


    As above. You will be supplying it with double its rated load.


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    #6
    Redisle
    Registered Users Posts: 1,849 ✭✭✭Redisle


    pieface_ie wrote: »
    As above. You will be supplying it with double its rated load.

    Think you'd actually be supplying 4 times it's rated load. Around 86W by my calculations. That thing would melt for sure.

    Op, given that it's a device for heating something I doubt it has a transformer, probably a simple heating element so you most
    definitely cannot plug this in here.


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    #7
    pieface_ie
    Closed Accounts Posts: 301 ✭✭pieface_ie


    Think you'd actually be supplying 4 times it's rated load. Around 86W by my calculations. That thing would melt for sure.

    Yes sorry Redsie you are correct, il know in future not to pull figures off the top of my head without calculating.

    P= V x I
    I= 20w/110 I= 0.1818181A

    V = I x Z
    Z= 110v/0.1818181A Z= 605ohms

    P= V*squared/Z
    P= 240*squared/605ohms P=95.20w

    95.20watts


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