the same cards two hands in a row

nacartai

Can somebody help me with this. WHat is the odds off getting the exact same 2 cards two hands in a row in texas holdem. For example you get the ace of dapdes and the ace of clubs twice in a row. I dont mean that you get any two aces twice in a row, I mean the exact same cards.
My read on it is that to get any two cards is like choosing 2 numbers in a 52 number lottery. Then to get them again it is 2 in a 52 lottery again.

But what I want to know is the odds of it happening twice. Is this like choosing 4 numbers in a 104 number lottery. If this is right what are the odds.

When getting the odds please explain the method you used. Thanks

Quazzie

Its the same as it happening once, unless you state what the two cards are before the first deal, thats when the odds accumulate.

For any two cards the odds of drawing those cards are 2/52 X 1/51 = 1/1326. This means that there are 1326 possible two card combinations that you can be dealt.
So, the odds of getting the same two cards as this hand in the next hand are 1/1326.
The odds of getting the same two specific cards in the next two hands (ie. getting KC and TD in the next two hands) are 1/1326 X 1/1326 = 1 in 1,758,276.
I hope that this helps.

LeixlipRed

There are 52 choose 2 possible starting hands in texas hold em. I.e theres a 1 in 1326 chance of getting a particular hand. So the chance of getting two exact hands in row is the square of that which is 1 in 1758276.

nacartai

lads , tanx very much. greatly appreciated

equivariant

Just to clarify this. The chances of getting a prespecified hand twice in a row is 1 in 1758276 (as per leixlipred's post). However, the chance of getting any hand twice in a row is 1 in 1326 (which is how I interpreted the OP's question)