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Second and subsequent derivatives

  • 21-10-2010 7:41pm
    #1
    Registered Users, Registered Users 2 Posts: 707 ✭✭✭


    If the derivative of a function is defined as the slope of that function, what is the second and third (and so on) derivatives defined as?


Comments

  • Moderators, Science, Health & Environment Moderators Posts: 1,852 Mod ✭✭✭✭Michael Collins


    The second derivative is sometimes called the curvature, the third one is...the rate of change of curvature! Maybe someone else has a better name for the third derivative.

    In mechanics though, if [latex] x [/latex] is a distance and [latex] t [/latex] is time, then [latex] \frac{dx}{dt} [/latex] is the velocity, [latex] \frac{d^2x}{dt^2} [/latex] is the acceleration, [latex] \frac{d^3x}{dt^3} [/latex] is the jerk, [latex] \frac{d^4x}{dt^4} [/latex] is the snap and I've heard [latex] \frac{d^5x}{dt^5} [/latex] and [latex] \frac{d^6x}{dt^6} [/latex] being refered to as crackle and pop, respectively (yes, seriously).


  • Registered Users, Registered Users 2 Posts: 13,076 ✭✭✭✭bnt


    The second derivative is the "slope of the slope", or course, and so on. The fun starts when you apply it e.g. when it's equal to zero, that marks an inflection point (change of curvature) in the original function. The second derivative test is used to find local minima and maxima in a function. When the function has two or more variables, you can build matrices of the various derivatives, which can be useful e.g. the Hessian. I'm sure other posters can go in to much more detail if necessary.

    It's also very useful in the physical sciences e.g. if f(t) is a function describing displacement (distance) w.r.t. time, then f'(t) is the velocity function, and f''(t) is the acceleration function. f'''(t) (change of acceleration w.r.t. time) is known as jerk. :p

    edit: snap!

    You are the type of what the age is searching for, and what it is afraid it has found. I am so glad that you have never done anything, never carved a statue, or painted a picture, or produced anything outside of yourself! Life has been your art. You have set yourself to music. Your days are your sonnets.

    ―Oscar Wilde predicting Social Media, in The Picture of Dorian Gray



  • Registered Users, Registered Users 2 Posts: 1,595 ✭✭✭MathsManiac


    I wouldn't be inclined (no pun intended) to say that the derivative was the slope of a function, and certainly wouldn't say that it was defined as the slope of the function. Slope is only defined (a priori, at least) for lines, so if you defined the derivative to be the slope the function, then the derivative would only be defined for linear functions, and that wouldn't be much use.


  • Registered Users, Registered Users 2 Posts: 2,481 ✭✭✭Fremen


    I wouldn't be inclined (no pun intended) to say that the derivative was the slope of a function, and certainly wouldn't say that it was defined as the slope of the function. Slope is only defined (a priori, at least) for lines, so if you defined the derivative to be the slope the function, then the derivative would only be defined for linear functions, and that wouldn't be much use.

    On the other hand, arguably the best way to think of the derivative is in terms of lines and slopes.

    A differentiable curve has the property that as you "zoom in" on a particular point on the curve, that point and its neighbours start to look more and more like a line. The derivative at the point is the slope of that line. Here are some pictures of f(x) = x^2, zooming in on the point x=.5:

    msp236219chehi7b70fb6hi.gif

    msp461719cheh49fc565357.gif

    msp357719cheh57g5625fh8.gif

    msp103819chebe70e55fggf.gif

    This point of view generalises very nicely to higher dimensions - a differentiable function from R^n to R^m starts to look more and more like a linear transform when you look at what it does to progressively smaller sets centered around a point p in R^n. The smaller the set, the more the function behaves like the Jacobian matrix at p.


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