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Electronic help

  • 08-10-2010 6:28pm
    #1
    blacklionboy
    Registered Users, Registered Users 2 Posts: 100 ✭✭


    Hi,

    Just doing thevinins theorem in college at the moment and I'm having issues fully understanding the method behind it.

    You find the equivalent resistance between the two nodes and thats your thevinin equivalent resistance.

    Then you find the thevinin equivalent voltage between the nodes a and b. However when your doing this you take into account the resistors used in the thevinin equivalent resistance.

    Then when you have written your equivalent circuit and are trying to find things like the load current on the other side of a and b, it seems the resistance has been accounted for twice in the Vth and Rth.

    Can anyone clear up why it still works for me?

    Thanks


Comments

  • #2
    blacklionboy
    Registered Users, Registered Users 2 Posts: 100 ✭✭blacklionboy


    like it seems more correct to just use V thevinin in the equivalent circuit as it has taken the resistances into account already.


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