Differentiation Help needed

wotzgoingon

Okay here is the equation:

A=(x+1)/x

i can get as far as this

=((x)(1)-(x+1)(1)/x^2

but i cant see how it goes to this answer

= -1/x^2

LeixlipRed

You need to expand the out the numerator and see if anything cancels.

The top line is:

(x)(1)-(x+1)(1)

Multiply out your brackets and see what you get.

wotzgoingon

LeixlipRed wrote: »

You need to expand the out the numerator and see if anything cancels.

The top line is:

(x)(1)-(x+1)(1)

Multiply out your brackets and see what you get.

I dont get what you mean like this:

(x-(x+1))/x^2

but i still dont see how it gets to the answer.

LeixlipRed

You still haven't expanded it fully.

x - (x+1) = x - x -1 = ?

wotzgoingon

LeixlipRed wrote: »

You still haven't expanded it fully.

x - (x+1) = x - x -1 = ?

so what your saying is x taken away from x so your left with -1/x^2 which is the answer. if thats the way cool. it had my head wrecked couldnt even do a simple sum.

sponsoredwalk

[latex] f(x) \ = \ \frac{x \ + \ 1}{x} [/latex]

[latex] f(x)\ = \ \frac{x}{x} \ + \ \frac{1}{x} [/latex]

[latex] f(x)\ = \ 1 \ + \ \frac{1}{x} [/latex]

[latex] \frac{d}{dx} f(x)\ = \ \frac{d}{dx} (1) \ + \ \frac{d}{dx} (\frac{1}{x}) [/latex]

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It's good that you used the quotient rule to do this as well though :cool: