Anyone Help me with Maths?

Les_Rebels123

here's the question:
express L: 4x-y+2+k(3x-3y+7)=0 in the form ax+by+c=0.
Hence find the value of k if the slope of L is 2.

So far ive got:
4x+3kx-y-3ky+2+7k=0 , and now I'm Stuck

Have i gone about it the wrong way?

Any help would be greatly appreciated!

thanks
Les_Rebels123

NU8

Factorise and get:
X(4+3k) - Y(1+3k) + 2k+7 = 0

Remember: Y = mX + c

Y(1+3k) = X(4+3k) + 2k+7
Y= X(4+3k/1+3k) + (2k+7/1+3k)
Therefore M = (4+3k/1+3k) = 2
2+6k = 4 + 3k
3k = 2
k = 2/3

I think that's it, hopefully someone will correct me if I'm wrong.

caroline1111

4x-y+2+k(3x-3y+7)=0
4x-y+2+3xk-3yk+7k
x(4+3k)+y(-1-3k)+2+7k=0
y(-1-3k)=(-4-3k)x-2-7k
y=-4-3k
-1-3k
=4+3k =2
1+3k
4+3k=2+6k
-3k=-2
k= 2/3

Keen2win

Oh jesus, that looks hard!

I think I'l drop down:D

NU8

caroline1111 wrote: »

4x-y+2+k(3x-3y+7)=0
4x-y+2+3xk-3yk+7k
x(4+3k)+y(-1-3k)+2+7k=0
y(-1-3k)=(-4-3k)x-2-7k
y=-4-3k
-1-3k
=4+3k =2
1+3k
4+3k=2+6k
-3k=-2
k= 2/3

That's exactly what I wrote
but since we both got the same answer I'm assuming that it is the correct one.