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  • 28-10-2009 11:08am
    #1
    Stephen Esquire
    Closed Accounts Posts: 61 ✭✭


    Desperately need help with this homework question:

    In 0.626 s, a 8.75-kg block is pulled through a distance of 3.55 m on a frictionless horizontal surface, starting from rest. The block has a constant acceleration and is pulled by means of a horizontal spring that is attached to the block. The spring constant of the spring is 453 N/m. By how much does the spring stretch?


    Thanks!


Comments

  • #2
    Podge_irl
    Moderators, Sports Moderators Posts: 28,138 Mod ✭✭✭✭Podge_irl


    The force the spring exerts is related to its extension by Hooke's Law, with the spring constant being the proportionality constant. You want to see how much force the block is under - this is equal to the force the spring is exerting. You get this from F = ma, so you need the acceleration of the block. You can get this from the usual linear equations of motion (v = u + at etc.)


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