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Chemistry Quesiton - Bleach Titration

  • 15-06-2009 7:40pm
    #1
    Registered Users, Registered Users 2 Posts: 555 ✭✭✭


    Yeah, for this experiment, how do you find out the dilution factor? In "Chemistry Live!" they have an example, and they multiply the moles/l by 10 to get the "original conecntration".

    How do you get that value?


Comments

  • Banned (with Prison Access) Posts: 1,211 ✭✭✭celtic723


    zodac wrote: »
    Yeah, for this experiment, how do you find out the dilution factor? In "Chemistry Live!" they have an example, and they multiply the moles/l by 10 to get the "original conecntration".

    How do you get that value?

    if they use 25cm^3 of bleach just always remember that it's a times 10 dilution and whatever moles you get for the undiluted bleach x 10 to get the undiluted.


  • Registered Users, Registered Users 2 Posts: 8,004 ✭✭✭ironclaw


    Say your have 25cm cubed of bleach and you put it in a 500cm volumetric flask which you then fill with water, you have diluted the bleach 20 times

    i.e. Thats 500cm divided by 25.
    celtic723 wrote: »
    if they use 25cm^3 of bleach just always remember that it's a times 10 dilution and whatever moles you get for the undiluted bleach x 10 to get the undiluted.

    Careful, the question can change. There is nothing to say they could use 75cm of bleach and dilute it to 800cm or similar. The dilution faction dones't have to be, but normally is, a whole number.


  • Closed Accounts Posts: 3,768 ✭✭✭almostnever


    Divide the final volume of the bleach solution by the volume of actual bleach used in the solution to get the dilution factor,if that makes sense. I am so bad at explaining things!


  • Closed Accounts Posts: 6 monkseyz


    the example in your book uses 25cm^3 of bleach and they dilute up to 250cm with deionised water. The dilution factor therefore is 10 ie. x10

    if it had been made up to 500 cm then the dilution factor would be 20. so divide the amount you made it up to by the amount of bleach used ie 250 * 25 = 10


  • Registered Users, Registered Users 2 Posts: 555 ✭✭✭zodac


    celtic723 wrote: »
    if they use 25cm^3 of bleach just always remember that it's a times 10 dilution and whatever moles you get for the undiluted bleach x 10 to get the undiluted.

    Is that because they use 250cm^3 or the value is always 10?


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  • Registered Users, Registered Users 2 Posts: 555 ✭✭✭zodac


    Ok thanks, that clears that section up.


  • Banned (with Prison Access) Posts: 1,211 ✭✭✭celtic723


    ironclaw wrote: »
    Say your have 25cm cubed of bleach and you put it in a 500cm volumetric flask which you then fill with water, you have diluted the bleach 20 times

    i.e. Thats 500cm divided by 25.



    Careful, the question can change. There is nothing to say they could use 75cm of bleach and dilute it to 800cm or similar. The dilution faction dones't have to be, but normally is, a whole number.

    they use 25cm^3 every year...not gonna change mate.


  • Registered Users, Registered Users 2 Posts: 8,004 ✭✭✭ironclaw


    celtic723 wrote: »
    they use 25cm^3 every year...not gonna change mate.

    It can, so never assume. :pac:


  • Closed Accounts Posts: 456 ✭✭aine-maire


    ironclaw wrote: »
    It can, so never assume. :pac:



    I think that we've all seen that assuming is BAD...(with Irish paper 2 in any case :o)


  • Closed Accounts Posts: 48 CallMeDoctor


    Cud u help me
    plz
    ? In the bleach titration why cant u use hydrochloric acid?
    Wat is the purpose of the sulfuric acid?
    Tanks !


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  • Closed Accounts Posts: 48 CallMeDoctor


    Cud u help me? In the bleach titration why cant u use hydrochloric acid?
    Wat is the purpose of the sulfuric acid?
    Tanks !


  • Posts: 4,630 ✭✭✭ [Deleted User]


    Don't use HCl as KMnO_4 oxidises the Cl- ions to Cl_2, thus affecting the titration.

    You've to use H_2SO_4 to provide the H+ ions, which are necessary for the reaction to take place. If there aren't enough H+ ions present, an intermediate stage of Mn(IV) is formed, which ruins the reaction. Providing enough H+ ions ensures that the Mn(VII) is fully reduced to Mn(II)


  • Closed Accounts Posts: 456 ✭✭aine-maire


    Cud u help me
    plz
    ?

    What did you need a spoiler for? :confused:


  • Closed Accounts Posts: 6 monkseyz


    what is the purpose of the potassium iodide? :(


  • Closed Accounts Posts: 456 ✭✭aine-maire


    monkseyz wrote: »
    what is the purpose of the potassium iodide? :(

    Ok that's been asked in like every single chemistry thread. Several times. :rolleyes:


    It's because a solution of iodine in potassium iodide is chemically the same as a solution of iodine. ie. I3 acts the same as I2

    We can't use iodine on its own, because it's not soluble in water and it vaporises at room temperature...

    God, I actually hope that's right! :o


  • Registered Users, Registered Users 2 Posts: 1,257 ✭✭✭JSK 252


    Basically the pottasium iodide is added as iodine is soluble in KI but not in water. The potassium iodide is kept in excess so that the full amount of the sodium hpyochlorite ions in the bleach react with the sodium thiosulfate in the burette such that the concentration of the ions can be determined.

    THE POTTASIUM IODIDE IS IN EXCESS.


  • Closed Accounts Posts: 48 CallMeDoctor


    confusing


  • Registered Users, Registered Users 2 Posts: 1,082 ✭✭✭Fringe


    these answers arent right because u dont use any iodine in the bleach experiment !!!!
    gettin confused with the thiosulfate titration!

    Hahahaha.

    (revise that experiment, it's probably coming up)


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