Maths Paper 2

Foirfe

Predictions??

Iwasfrozen

Well, expect Mac Laurin and ratio test to come up in Q8.

phasers

Which level?

ayapatrick

Iwasfrozen wrote: »

Well, expect Mac Laurin and ratio test to come up in Q8.

id say maybe for coord geom line the proof that a transformaion maps every pair of lines onto another pair!
i doubt perp distance will, it was up last year but gonna learn it just in case!

rcaz

My teacher was saying, because there was so little theory on Paper 1, they might compensate on Paper 2. So I'm not taking any chances with trig and line proofs.

Max/Min problems for Q8 too. But they're not so bad.

Foirfe

Higher level??

KokaNoodles

I heard trigonometry might come up. but thats jus a huntch, it came up last year tho so....

awhir

KokaNoodles wrote: »

I heard trigonometry might come up. but thats jus a huntch, it came up last year tho so....

oh rly ! if it came up last year i dont think it will come up this year i wish !

yummy91

it was on the radio the last night that the perpindicular proof that was on last year was answered terribly so theres a good chance that it'll come up..... i didn't even know there was a perpindicular proof until he said it!!

croker1

ok well im doin OL unlike all you brainiacs!! but eh i was just wondering if someone could help me with a slight problem to do with linear programming??

ok so if your given an equation such as 2x+3y-6=0 how do you find the 2 points??????????

this is probobly so simple bcoz it didn even explain in the book it just said that the points wer (3,0) and (0,2) ....

thanks in advance:D

Foirfe

Jes ur gas KoKaNoodles
Sad sad joke...

yummy91

croker1 wrote: »

ok well im doin OL unlike all you brainiacs!! but eh i was just wondering if someone could help me with a slight problem to do with linear programming??

ok so if your given an equation such as 2x+3y-6=0 how do you find the 2 points??????????

this is probobly so simple bcoz it didn even explain in the book it just said that the points wer (3,0) and (0,2) ....

thanks in advance:D

i think that you just let y=0 and work out for x
then let x= 0 and work out for y
then the points are (x,0) and (0,y)

i think anyway, but i'm kinda dead if i got that wrong

awhir

yummy91 wrote: »

i think that you just let y=0 and work out for x
then let x= 0 and work out for y
then the points are (x,0) and (0,y)

i think anyway, but i'm kinda dead if i got that wrong

yep , those are the 2 pionts were that line cuts both axises.

**Timbuk2**

croker1 wrote: »

ok well im doin OL unlike all you brainiacs!! but eh i was just wondering if someone could help me with a slight problem to do with linear programming??

ok so if your given an equation such as 2x+3y-6=0 how do you find the 2 points??????????

this is probobly so simple bcoz it didn even explain in the book it just said that the points wer (3,0) and (0,2) ....

thanks in advance:D

You're referring to the two points where the line cuts the x-axis and the y-axis.

When the line cuts the y-axis, x=0. Therefore, let x=0
2x+3y-6=0 -> 3y-6 = 0 -> y=2 therefore point = (0,2)

I won't do the whole question as you won't learn that way, but you get the general idea. Remember, if a line crosses the y-axis, x=0, and if it crosses the x-axis, y=o

croker1

thanks lads!!!

i seem so stupid its simple!!

bythewoods

El Pr0n wrote: »

My teacher was saying, because there was so little theory on Paper 1, they might compensate on Paper 2. So I'm not taking any chances with trig and line proofs.

Max/Min problems for Q8 too. But they're not so bad.

I think that's actually a very valid point. Won't be skimping, so!
Thanks d00d.

~Candy~

yummy91 wrote: »

it was on the radio the last night that the perpindicular proof that was on last year was answered terribly so theres a good chance that it'll come up..... i didn't even know there was a perpindicular proof until he said it!!

are you serious? i thought they all did good last yr..like it was well predicated!!!:rolleyes: it's not as if the dept would ran out of Qs to ask......

Blue_Rose

The angle between 2 lines proof for question 3!

spoonbadger

yummy91 wrote: »

i think that you just let y=0 and work out for x
then let x= 0 and work out for y
then the points are (x,0) and (0,y)

i think anyway, but i'm kinda dead if i got that wrong

THAT's all there is to linear programming?!.


Jaysis :pac:.

/higher level smugness