Advertisement
If you have a new account but are having problems posting or verifying your account, please email us on hello@boards.ie for help. Thanks :)
Hello all! Please ensure that you are posting a new thread or question in the appropriate forum. The Feedback forum is overwhelmed with questions that are having to be moved elsewhere. If you need help to verify your account contact hello@boards.ie
Hi there,
There is an issue with role permissions that is being worked on at the moment.
If you are having trouble with access or permissions on regional forums please post here to get access: https://www.boards.ie/discussion/2058365403/you-do-not-have-permission-for-that#latest

Unknown power?

  • 26-05-2009 7:34pm
    #1
    Closed Accounts Posts: 134 ✭✭


    Hey all,

    I was given this equation (distance to a star)

    D = 10^m-M+5/5

    where D is distance, m is apperant magnitude, M is absolute magnitude.

    A question gives the distance and M, but needs you to find the apperant mag.

    you end up with

    7.76=10^4.42+m/5, but how do you get the M out of the indices and down somewhere manageable. I was thinking Logs, so

    Log10(7.76)=Log10(10)^4.42+m/5

    Log10(7.76)=4.42+m/5, and so on


    But is this the right way to do it?

    Thanks,
    _Kar


Comments

  • Registered Users, Registered Users 2 Posts: 1,595 ✭✭✭MathsManiac


    Without brackets, that equation you gave is not as it should be.

    The correct equation is, I think: D = 10^[(m-M+5)/5]

    You can put the numbers in first and then rearrange, or you can rearrange first:

    log(D) = (m-M+5)/5 (log being to the base 10)
    5*log(D) = m-M+5
    5*log(D) + M - 5 = m.

    You should be ok from there.


Advertisement