Advertisement
If you have a new account but are having problems posting or verifying your account, please email us on hello@boards.ie for help. Thanks :)
Hello all! Please ensure that you are posting a new thread or question in the appropriate forum. The Feedback forum is overwhelmed with questions that are having to be moved elsewhere. If you need help to verify your account contact hello@boards.ie
Hi there,
There is an issue with role permissions that is being worked on at the moment.
If you are having trouble with access or permissions on regional forums please post here to get access: https://www.boards.ie/discussion/2058365403/you-do-not-have-permission-for-that#latest

Can Someone Finish This Equation

  • 15-04-2009 5:25pm
    #1
    O.P.H
    Registered Users, Registered Users 2 Posts: 856 ✭✭✭


    KMnO4 + NaOH + KI = :confused:


Comments

  • #2
    eZe^
    Registered Users, Registered Users 2 Posts: 7,046 ✭✭✭eZe^


    KMnO4 + 2NaOH + 2KI = 3KOH + MnO2 + Na2O + I2.


  • #3
    O.P.H
    Registered Users, Registered Users 2 Posts: 856 ✭✭✭O.P.H


    Cheers but how sure are you. I thought the KIO3 and MnO42- manganate ion should form


  • #4
    eZe^
    Registered Users, Registered Users 2 Posts: 7,046 ✭✭✭eZe^


    Not sure at all man, I'm a physicist, and just tried to balance the elements... :pac:


  • #5
    DemocAnarchis
    Registered Users, Registered Users 2 Posts: 404 ✭✭DemocAnarchis


    As far as i can tell from a quick search, KIO3 is usually prepared with KOH and I2. Therefore, im going to guess that the K+ of the permanganate displaces the Na of the salt, then the KOH and KI react to form KIO3

    Rough guess: 3 KMnO4 + 3 KI + 3 NaOH -> KIO3 + 3 NaMnO4 + 3 KH + 2 K+

    Fairly sure thats wrong, i'll have a look at it later


  • #6
    O.P.H
    Registered Users, Registered Users 2 Posts: 856 ✭✭✭O.P.H


    eZe^ wrote: »
    Not sure at all man, I'm a physicist, and just tried to balance the elements... :pac:

    Well ya little pup, wait there till I get ya ;)

    I'm fairly sure this is the overall reaction in oxidation state terms, its just finishing it off

    MnO4(-) + I(-) + 6OH(-) = MnO4(2-) + IO3(-) + 3H2O + 5e-


  • Advertisement
Advertisement