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Can Someone Finish This Equation

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  • 15-04-2009 6:25pm
    #1
    O.P.H
    Registered Users Posts: 856 ✭✭✭


    KMnO4 + NaOH + KI = :confused:


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    #2
    eZe^
    Registered Users Posts: 7,046 ✭✭✭eZe^


    KMnO4 + 2NaOH + 2KI = 3KOH + MnO2 + Na2O + I2.


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    #3
    O.P.H
    Registered Users Posts: 856 ✭✭✭O.P.H


    Cheers but how sure are you. I thought the KIO3 and MnO42- manganate ion should form


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    #4
    eZe^
    Registered Users Posts: 7,046 ✭✭✭eZe^


    Not sure at all man, I'm a physicist, and just tried to balance the elements... :pac:


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    #5
    DemocAnarchis
    Registered Users Posts: 404 ✭✭DemocAnarchis


    As far as i can tell from a quick search, KIO3 is usually prepared with KOH and I2. Therefore, im going to guess that the K+ of the permanganate displaces the Na of the salt, then the KOH and KI react to form KIO3

    Rough guess: 3 KMnO4 + 3 KI + 3 NaOH -> KIO3 + 3 NaMnO4 + 3 KH + 2 K+

    Fairly sure thats wrong, i'll have a look at it later


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    #6
    O.P.H
    Registered Users Posts: 856 ✭✭✭O.P.H


    eZe^ wrote: »
    Not sure at all man, I'm a physicist, and just tried to balance the elements... :pac:

    Well ya little pup, wait there till I get ya ;)

    I'm fairly sure this is the overall reaction in oxidation state terms, its just finishing it off

    MnO4(-) + I(-) + 6OH(-) = MnO4(2-) + IO3(-) + 3H2O + 5e-


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