Advertisement
If you have a new account but are having problems posting or verifying your account, please email us on hello@boards.ie for help. Thanks :)
Hello all! Please ensure that you are posting a new thread or question in the appropriate forum. The Feedback forum is overwhelmed with questions that are having to be moved elsewhere. If you need help to verify your account contact hello@boards.ie
Hi there,
There is an issue with role permissions that is being worked on at the moment.
If you are having trouble with access or permissions on regional forums please post here to get access: https://www.boards.ie/discussion/2058365403/you-do-not-have-permission-for-that#latest

light?

  • 05-03-2009 8:55pm
    #1
    Registered Users, Registered Users 2 Posts: 3,532 ✭✭✭


    with regards einstein's e=mc^2, we studied it a while ago in class (i only do phys/chem as it's a small school) i ub=nderstand the principles of it but

    WHY exactly is c^2 used as the constant value in this calculation?


Comments

  • Closed Accounts Posts: 649 ✭✭✭fillmore jive


    as c is the value of light in a vacumm. the whole idea of this equaion is that mass is equivalant to energy, and that the c^2 constant is required to convert mass to energy in terms of units.


  • Closed Accounts Posts: 8,015 ✭✭✭CreepingDeath


    WHY exactly is c^2 used as the constant value in this calculation?

    Because the atoms are square shaped.


  • Registered Users, Registered Users 2 Posts: 861 ✭✭✭Professor_Fink


    WHY exactly is c^2 used as the constant value in this calculation?

    Because in special relativity the speed of light (c) is constant in all reference frames. The whole of relativity is built upon this assumption. If a different velocity (f) was constant between frames, then we would have f^2 as the constant.


  • Registered Users, Registered Users 2 Posts: 1,501 ✭✭✭Delphi91


    Because in special relativity the speed of light (c) is constant in all reference frames. The whole of relativity is built upon this assumption. If a different velocity (f) was constant between frames, then we would have f^2 as the constant.

    I'm not sure, but I think ginga was wondering why it's specifically c^squared as against, say, c^3 or c^(1/2), etc


  • Registered Users, Registered Users 2 Posts: 861 ✭✭✭Professor_Fink


    Delphi91 wrote: »
    I'm not sure, but I think ginga was wondering why it's specifically c^squared as against, say, c^3 or c^(1/2), etc

    The calculation can be found here: http://en.wikipedia.org/wiki/Kinetic_energy#Relativistic_kinetic_energy_of_rigid_bodies

    Trivially you can only have a velocity squared as the constant, since otherwise the units don't match.


  • Advertisement
  • Moderators, Recreation & Hobbies Moderators, Science, Health & Environment Moderators, Technology & Internet Moderators Posts: 93,567 Mod ✭✭✭✭Capt'n Midnight


    E=mc%5E2.jpg


  • Registered Users, Registered Users 2 Posts: 1,230 ✭✭✭chem


    I have often wondered, If a craft was close to the speed of light. And it fired its guns (bullets/ laser) would the projectile not then be moving faster then the speed of light?


  • Moderators, Computer Games Moderators, Technology & Internet Moderators, Help & Feedback Category Moderators Posts: 25,757 CMod ✭✭✭✭Spear


    chem wrote: »
    I have often wondered, If a craft was close to the speed of light. And it fired its guns (bullets/ laser) would the projectile not then be moving faster then the speed of light?

    No, velocities do not add linearly.


  • Moderators, Society & Culture Moderators Posts: 9,689 Mod ✭✭✭✭stevenmu


    chem wrote: »
    I have often wondered, If a craft was close to the speed of light. And it fired its guns (bullets/ laser) would the projectile not then be moving faster then the speed of light?

    That's what makes relativity so cool. If the craft fires it's lasers forward, observers on the craft will see the lasers move away from them at the speed of light. Somebody standing still off to the side watching this would see the lasers moving off at the speed of light, and if the craft was travelling at say 3/4s the speed of light, the laser would appear to be going 1/4 the speed of light faster than the craft.

    There's obviously a discrepancy here in the speed of the laser being observed in the two frames of reference (one frame of reference being on the craft, the other being off to the side watching). Observers on the craft see the laser move away from them at the speed of light, observers to the side see it move away from the craft at 1/4 the speed of light. Relativity solves this by linking in time, if we say that time is slower for those who are travelling on the craft than for those who are at rest watching it, that allows those on the craft to experience the laser moving away at the speed of light while those who are at rest can watch it move away from the craft at 1/4 the speed of light. And it turns out this is exactly the case, the faster something travels, the slower it experiences time, you've probably heard the example that if someone was to take of from earth and travel at near the speed of light for 100 years they might come back and only 1 year will have passed for them.

    Now ... have fun wondering what would happen if two craft flying directly towards each other, both travelling nearly the speed of light, fired their lasers at each other :pac:


  • Moderators, Recreation & Hobbies Moderators, Science, Health & Environment Moderators, Technology & Internet Moderators Posts: 93,567 Mod ✭✭✭✭Capt'n Midnight


    stevenmu wrote:
    Now ... have fun wondering what would happen if two craft flying directly towards each other, both travelling nearly the speed of light, fired their lasers at each other :pac:
    Lots of blue shift so you would get a dose of gamma rays, you'd either turn into the hulk or die bald.


  • Advertisement
  • Closed Accounts Posts: 206 ✭✭eagleye7


    the way we were told in lectures had to do with assuming a light particle had a momentum = mass times velocity which brings in the c value. i did it last year sometime i could dig out my notes and explain if you want but it went somethin like:

    imagine you have a laser in a box. when it fires a photon there should be a very small recoil, this means the box moves and unless the light has a momentum then the system defies the law of conservation of momentum, this brings in the fact that the light must have had some mass associated with it, and as a result mass has energy associated with it


Advertisement