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Changing the subject of an equation

  • 11-10-2008 2:41pm
    #1
    Chet T16
    Registered Users, Registered Users 2 Posts: 2,320 ✭✭✭


    I'm having trouble getting t as the subject of this equation, in particular getting the 3at seperated

    3at+2(b-t)=4t+5

    Any pointers please :)


Comments

  • #2
    mathew
    Registered Users, Registered Users 2 Posts: 1,488 ✭✭✭mathew


    3at+2(b-t)=4t+5
    3at+2b-2t=4t+5
    3at-2t-4t=5-2b
    3at-6t=5-2b
    t(3a-6)=5-2b
    t=(5-2b)/(3a-6)


  • #3
    Chet T16
    Registered Users, Registered Users 2 Posts: 2,320 ✭✭✭Chet T16


    mathew wrote: »
    3at+2(b-t)=4t+5
    3at+2b-2t=4t+5
    3at-2t-4t=5-2b
    3at-6t=5-2b
    t(3a-6)=5-2b
    t=(5-2b)/(3a-6)

    Aha, i see. The highlighted section was where i was stumped.

    Thank you!


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