Advertisement
If you have a new account but are having problems posting or verifying your account, please email us on hello@boards.ie for help. Thanks :)
Hello all! Please ensure that you are posting a new thread or question in the appropriate forum. The Feedback forum is overwhelmed with questions that are having to be moved elsewhere. If you need help to verify your account contact hello@boards.ie
Hi there,
There is an issue with role permissions that is being worked on at the moment.
If you are having trouble with access or permissions on regional forums please post here to get access: https://www.boards.ie/discussion/2058365403/you-do-not-have-permission-for-that#latest

Changing the subject of an equation

  • 11-10-2008 02:41PM
    #1
    Chet T16
    Registered Users, Registered Users 2 Posts: 2,320 ✭✭✭


    I'm having trouble getting t as the subject of this equation, in particular getting the 3at seperated

    3at+2(b-t)=4t+5

    Any pointers please :)


Comments

  • #2
    mathew
    Registered Users, Registered Users 2 Posts: 1,488 ✭✭✭mathew


    3at+2(b-t)=4t+5
    3at+2b-2t=4t+5
    3at-2t-4t=5-2b
    3at-6t=5-2b
    t(3a-6)=5-2b
    t=(5-2b)/(3a-6)


  • #3
    Chet T16
    Registered Users, Registered Users 2 Posts: 2,320 ✭✭✭Chet T16


    mathew wrote: »
    3at+2(b-t)=4t+5
    3at+2b-2t=4t+5
    3at-2t-4t=5-2b
    3at-6t=5-2b
    t(3a-6)=5-2b
    t=(5-2b)/(3a-6)

    Aha, i see. The highlighted section was where i was stumped.

    Thank you!


Advertisement