Maths

Nato!

any chance anyone can compile all the maths formulas into each question (ordinary)

gaz d

You would learn more if you did it yourself. i did it.

Nato!

yea thats true but i need a fast fix if you know what i mean;);)

Nato!

just learned -b formula

Gavin "shels"

Pm.

Challenged

Here are the formulae for each question.
Formulae in red need to be learnt whereas formulae in black are to be found in the table book.
http://www.studentxpress.ie/formulae.pdf

gaz d

Can someone explain how this ( 10 + 2y )2 goes to this
100+40y+4y2
I know its probably easy but i cant figure it out!:mad:

Spud83

(10 + 2y)2 =

(10 + 2y) * (10 + 2y) =

100 + 20y + 20y + 4y2 =

100 + 40y + 4y2

Nato!

gaz d wrote: »

Can someone explain how this ( 10 + 2y )2 goes to this
100+40y+4y2
I know its probably easy but i cant figure it out!:mad:

it looks like you multiply the bracket by itself IE.
(10+2y)(10+2y)

gaz d

Yeah but where does the 40y come from

gaz d

alanmurphy83 wrote: »

(10 + 2y)2 =

(10 + 2y) * (10 + 2y) =

100 + 20y + 20y + 4y2 =

100 + 40y + 4y2

Thanks man i get it now!!!:D

salman85

square the first


twice the first by the second

square the last

Nato!

we should do a maths quiz !!
it will make wasting time on this productive!!

awww... thank god I'm not doing maths...

Nailz

Can someone here explain the Newton-Raphson Method? Driving me mad!
The question is; Take x1=4 as the first approximation of a real root of x^(3)-4x^(2)-5=0

Find using the Newton-Raphson Method, x2, the second approximation.

Cokehead Mother

You have f(x). You sub in 4 to get f(x_1).

You differentiate f(x) to get f'(x). You sub in 4 to get f'(x_1).

You use the formula

, with x_1 instead of x_n and x_2 instead of x_[n+1] and you're done.