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Rate Law and rate constant

  • 30-03-2008 5:51pm
    #1
    Registered Users, Registered Users 2 Posts: 922 ✭✭✭


    Given the below reaction

    2NO+2H2 ---> N2+2H2O

    and the following data, how can I work out the rate law and the rate constant.

    [NO]/mol/L [H2]/mol/L Rate/mol/L/s
    0.025 0.025 0.99x10^-4
    0.050 0.025 3.96x10^-4
    0.050 0.075 11.88x10^-4

    I know that the rate=k[NO]^n[H2]^m

    But how do you work out n and m?


Comments

  • Closed Accounts Posts: 6,151 ✭✭✭Thomas_S_Hunterson


    AFAIK, n and m are the coefficients in the chamical equation, so 2 and 2 respectively.


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