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php - number_format()

  • 18-06-2007 7:27pm
    #1
    Ziycon
    Registered Users, Registered Users 2 Posts: 1,987 ✭✭✭


    Im formating a number say 6.788 and with the number is being rounded up to 7 by number_format or or 439.978 rounded to 440, is there a way i can tell the it to only take characters from the left side of the decimal point with out rounding up or down?


Comments

  • #2
    Ph3n0m
    Closed Accounts Posts: 4,655 ✭✭✭Ph3n0m


    you could do this
    $number = "34.234234234234";
$integer = explode(".", $number);

echo $integer[0];


  • #3
    Ziycon
    Registered Users, Registered Users 2 Posts: 1,987 ✭✭✭Ziycon


    Ph3n0m wrote:
    you could do this
    $number = "34.234234234234";
$integer = explode(".", $number);

echo $integer[0];

    Fair play to you.:D I know theres a way to do all these little things but its hard to know what to search for on the php.net site!


  • #4
    daymobrew
    Registered Users, Registered Users 2 Posts: 6,571 ✭✭✭daymobrew


    You could use floor();

    I had also tried sprintf: [PHP]$fNum = 6.788;
    echo sprintf( '%d - %.0f', $fNum, $fNum ); // Printed "6 - 7"[/PHP]


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