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Differentiation Question

  • 14-05-2007 5:23pm
    #1
    Sinfonia
    Registered Users, Registered Users 2 Posts: 3,854 ✭✭✭


    Hello,


    I'm puzzled over finding the Derivate for:

    ln(1+e)+w-0.5(1+e)^2


    My lecture notes say:

    b/(1+e) - (1+e) = 0

    (Does this mean we are differentiating with respect to (1+e), or just e?)


    For the last term (after the minus) I understand how that was achieved, and the w disappears, but I don't understand the first part, i.e.

    ln(1+e)

    I know that the derivative for ln(1+e) would be 1/(1+e), but how does the b end up on top, assuming it has to be part of the equation and not just multiplied at the end:confused:

    Thanks in advance


Comments

  • #2
    Irish Wolf
    Registered Users, Registered Users 2 Posts: 2,178 ✭✭✭Irish Wolf


    ln(1+e) = b(ln(1+e))

    => derivative = b(1/(1+e)) = b/(1+e)


  • #3
    Sinfonia
    Registered Users, Registered Users 2 Posts: 3,854 ✭✭✭Sinfonia


    Irish Wolf wrote:
    ln(1+e) = b(ln(1+e))

    => derivative = b(1/(1+e)) = b/(1+e)

    Thanks IW,

    (Just for clarification):
    So the b is just multiplied at the end, and that's all there is to it?


  • #4
    Irish Wolf
    Registered Users, Registered Users 2 Posts: 2,178 ✭✭✭Irish Wolf


    Yeah - it's a constant treated the same as the 0.5 in the final term.


  • #5
    Sinfonia
    Registered Users, Registered Users 2 Posts: 3,854 ✭✭✭Sinfonia


    Brilliant, cheers :)


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