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XSLT problem

  • 11-05-2007 10:33am
    #1
    warrenaldo
    Registered Users, Registered Users 2 Posts: 500 ✭✭✭


    I am a newbie to xslt.

    I have a param defined in my xml(before transform) lets call it XXX

    To access this in the xslt i use $XXX - which is ok.

    How do i output my text aswell as the value of $XXX

    But i have ouput to my RSS file that says
    Hello $XXX

    So my xslt should look like ?
    <xsl:if test="RES">
    <title>Your name is : $XXX </title>
    </xsl:if>

    How can i output this?


Comments

  • #2
    Inspector Gadget
    Registered Users, Registered Users 2 Posts: 1,393 ✭✭✭Inspector Gadget


    Off the top of my head:

    <xsl:value-of select="$XXX"/>

    Do a google for the Mulberry Technologies XSLT/Xpath quick reference, it's very handy for this sort of thing...

    Gadget


  • #3
    warrenaldo
    Registered Users, Registered Users 2 Posts: 500 ✭✭✭warrenaldo


    cheers,it looks like i can just do that and append my stuff to the fronth of it ie :

    Hello <xsl:value-of select="$XXX"/>

    works perfect - cheers.


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