Advertisement
If you have a new account but are having problems posting or verifying your account, please email us on hello@boards.ie for help. Thanks :)
Hello all! Please ensure that you are posting a new thread or question in the appropriate forum. The Feedback forum is overwhelmed with questions that are having to be moved elsewhere. If you need help to verify your account contact hello@boards.ie
Hi there,
There is an issue with role permissions that is being worked on at the moment.
If you are having trouble with access or permissions on regional forums please post here to get access: https://www.boards.ie/discussion/2058365403/you-do-not-have-permission-for-that#latest

Pascal's Pyramid

  • 08-04-2007 10:19am
    #1
    Closed Accounts Posts: 14


    Any of you come across the multinomial theorem?
    Is it ever used in solving statistical problems?

    Pascal's Tetrahedron (Pascal's Pyramid)...
    1
    1
    1 1
    1
    2 2
    1 2 1
    1
    3 3
    3 6 3
    1 3 3 1
    1
    4 4
    6 12 6
    4 12 12 4
    1 4 6 4 1
    1
    5 5
    10 20 10
    10 30 30 10
    5 20 30 20 5
    1 5 10 10 5 1


Comments

  • Closed Accounts Posts: 2,980 ✭✭✭Kevster


    I have been using this frequently for the past two years. It is used for statistics and probability. For example, the Binomial Probability formula.

    Ah! - Excellent! I found an excellent link that shows how it's used:

    http://www.krysstal.com/binomial.html


    ...I couldn't be arsed explaining myself :rolleyes:


  • Registered Users, Registered Users 2 Posts: 39,900 ✭✭✭✭Mellor


    The one I was familar with was the same as all the bottom lines of your triangles,
    1
    1 1
    1 2 1
    1 3 3 1
    1 4 6 4 1
    1 5 10 10 5 1
    1 6 15 20 15 6 1
    1 7 21 35 35 21 7 1
    1 8 28 56 70 56 28 8 1
    1 9 36 84 126 126 84 36 9 1

    What are the extra numbers in yours.
    We used to in probability and in alegbra, (x+y)^n is the nth line on the triangle. with x^n reducing, y^0 increasing


  • Closed Accounts Posts: 14 Precision


    The Binomial Probability is used for calculating the probability when throwing a 2 sided coin a number of times.

    Trinomial probability would be used for calculating the probability when throwing an object that could land on one of 3 possible sides.

    Tetranomial probability would be used for calculating the probability when throwing a tetrahedron dice (4 sided dice, d4).
    Hexanomial probability would be used for calculating the probability when throwing a cubic dice (6 sided dice, d6).
    Octanomial probability would be used for calculating the probability when throwing a octahedron dice (8 sided dice, d8).

    Likewise, a d12 is a dodecahedron dice (12 sided dice) and a d20 is a icosahedron dice (20 sided dice).

    Say if a d20 dice was thrown a large number of times, although any arrangement of numbers is possible, some overall combinations of numbers are far more likely to occur than other combinations.

    I am not sure though whether the mathematics would get to difficult. I think there would be a lot of recursion in the maths.
    BluePlatonicDice.jpg


  • Closed Accounts Posts: 14 Precision


    Pascal's Triangle is a two dimenional layout of the coefficients that are used in the binomial theorem.
    The Binomial Theorem
    Here there are two elements, a and b.
    The expansion of (a + b)^n for n = 0, 1,…, 5:

    (a + b)^0 = 1
    (a + b)^1 = 1(a) + 1(b)
    (a + b)^2 = 1(a.a) +2(a.b) + 1(b.b)
    (a + b)^3 = 1(a.a.a) +3(a.a.b) + 3(a.b.b) + 1(b.b.b)
    (a + b)^4 = 1(a.a.a.a) +4(a.a.a.b) + 6(a.a.b.b) +4(a.b.b.b) + 1(b.b.b.b)
    (a + b)^5 = 1(a.a.a.a.a) +5(a.a.a.a.b) +10(a.a.a.b.b) +10(a.a.b.b.b) +5(a.b.b.b.b) +1(b.b.b.b.b)

    Pascal's Tetrahedron is a three dimenional layout of the coefficients that are used in the trinomial theorem.
    The Trinomial Theorem
    Here there are three elements, a, b and c.
    The expansion of (a + b + c)^n for n = 0, 1,…, 3:

    (a + b + c)^0 = 1
    (a + b + c)^1 = 1(a) + 1(b) + 1(c)
    (a + b + c)^2 = 1(a.a) +2(a.b) + 2(a.c) + 2(b.c) + 1(b.b) + 1(c.c)
    (a + b + c)^3 = 1(a.a.a) +3(a.a.b) +3(a.b.b) +1(b.b.b) +6(a.b.c) +3(a.a.c)+3(a.c.c)+3(b.b.c)+3(b.c.c)+1(c.c.c)

    Multinomial theorems, with a higher number of elements, would have a higher dimensional layout of coefficients.

    The tetranomial theorem, is used when there are four elements, and its layout of coefficients is four dimensional.


Advertisement