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Confused by resistance question

  • 20-02-2007 11:49am
    #1
    Closed Accounts Posts: 1,836 ✭✭✭


    In the question there's a 24vdc power supply connected to a bank of 10 6W, 24vdc solenoid valves in another cabinet by a 100m copper cable (resistivity of copper given).
    The first question is to calculate the resistance of the cable (no bother).
    The next question is to calculate the resistance of each solenoid? How the hell am I supposed to do this, I don't think there's enough info provided?
    Any help appreciated...

    untitledub6.jpg


Comments

  • Registered Users, Registered Users 2 Posts: 441 ✭✭robfitz


    This should be solvable using Watt's Law or similar.


  • Moderators, Science, Health & Environment Moderators Posts: 1,852 Mod ✭✭✭✭Michael Collins


    Yeh it's solvable using Joule's Law. The trick is that the solenoids consume 6 W when an ideal voltage source of 24 V is placed across them.

    You can work out the resistance from this.


  • Registered Users, Registered Users 2 Posts: 2,738 ✭✭✭mawk


    sorry.. maybe im way off here but

    p=VI

    so

    I=6/24

    .25

    and
    p=r X I^2

    =>

    6/.25^2=r

    r= 16ohms

    sum R's = 160ohms?

    am i missing something important? probably.. im pretty tired


  • Moderators, Science, Health & Environment Moderators Posts: 1,852 Mod ✭✭✭✭Michael Collins


    All good except for your calculations! But that's the method alright.

    You don't need to find the current really, just use P=V²/R.

    No need to add up the resistances. The question wants in individual resistance of each coil, which is the same for each and
    close to 100 ohms!


  • Registered Users, Registered Users 2 Posts: 2,738 ✭✭✭mawk


    All good except for your calculations! But that's the method alright.

    [/SPOILER]


    well i did them in my head at two in the morning..


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  • Closed Accounts Posts: 1,836 ✭✭✭BigCon


    Cheers Guys, looks obvious now...


  • Registered Users, Registered Users 2 Posts: 2,738 ✭✭✭mawk


    yeah no problem, any time


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