convert timestamp hhmmss to seconds?

jon1981

Hi,

i want to subtract two timestamps in unix, does anyone have a quick script for this? be it perl, shell whatever? the timestamp is of format hhmmss.

Steveire

Here's some python:

#!/usr/bin/env python
import datetime
def getDifference(timestamp1, timestamp2):
  hours1, minutes1, seconds1 = int(timestamp1[0:2]), int(timestamp1[2:4]), int(timestamp1[4:6])
  hours2, minutes2, seconds2 = int(timestamp2[0:2]), int(timestamp2[2:4]), int(timestamp2[4:6])
  t1 = datetime.datetime(1, 1, 1, hours1, minutes1, seconds1)
  t2 = datetime.datetime(1, 1, 1, hours2, minutes2, seconds2)
  difference = t1 - t2
  return difference.seconds

timestamp1 = "112233"
timestamp2 = "111010"
print getDifference(timestamp1, timestamp2)
# Prints 743

jon1981

#!/usr/bin/perl


sub convert_time{

$time_in="$_[0]";
$time_in=~/(\d{2})(\d{2})(\d{2})/;

$hour = $1;
$min = $2;
$sec = $3;

$time_sec = $sec + ($min*60) + ($hour*3600);

}

$time_end = $ARGV[0];
$time_start = $ARGV[1];
$duration = convert_time($time_end) - convert_time($time_start);
print "$duration\n";

cheers but i got off my lazy ass, this is crude but works

niallb

You want crude? I'll give you crude :-)
Bash style Shell - all on one line.

for ts in 165959 090000 ; \
do echo 60*$(echo $ts | cut -c 1-2,3-4,5-6 --output-delimiter="*60+")   ;\
 done | paste -d- - - | bc

Ugly as sin, but when I press Return - I want answers :-)

NiallB

Khannie

Do your own homework tbh. (A perl version of this thread was posted in the programming forum).

jon1981

niallb wrote:

You want crude? I'll give you crude :-)
Bash style Shell - all on one line.

for ts in 165959 090000 ; \
do echo 60*$(echo $ts | cut -c 1-2,3-4,5-6 --output-delimiter="*60+")   ;\
 done | paste -d- - - | bc

Ugly as sin, but when I press Return - I want answers :-)

NiallB

damn!!!