A quick and easy formula

Scouser in Dub

for two of your suit flopping can't seem to think of an easy way of formulating this as an equation and I am sure it is dead simple so anyone that can please do

Ste05

Not sure about the formula for working it out, but it's 8.1/1, here's a link to all sorts of useful odds.

http://www.planetstacked.com/holdem/odds/

Scouser in Dub

Cheers thanks for that but if anyone has the workings out that would be appreciated also

there's some really cool stuff there thanks Ste

Hitman Actual

Scouser in Dub wrote:

for two of your suit flopping can't seem to think of an easy way of formulating this as an equation and I am sure it is dead simple so anyone that can please do

Two in your hand?

Prob = [(11C2)x(50-11)]/50C3
=[((11x10)/(2*1))x39)/((50*49*48)/(3*2*1))]
= 0.1094
= ~8.1/1

where 11C2 is the combination of flush cards left to flop in twos, which can be combined with the other 39 non-suited cards; 50C3 is the number of flop combinations not counting your two hole cards.

Brayruit

An easier way (I think) to think it through...

prob of exactly 2 of your suit hitting the flop (i.e. excluding probability of 3):

prob first card is S = 11 / 50 (11 left in your suit from 50 unseen cards)
prob 2nd card is S = 10 / 49
prob 3rd card is NOT S = 39 / 48 (39 of remaining 48 cards are not your suit)

This is probability of SSX. Also need SXS and XSS, so multiply answer by 3

So the sum is 3 x 11/50 x 10/49 x 39/48 = 0.1094 which is 8.14 to 1

If you want to add in the probability of SSS (i.e. all 3 in your suit) it is
11/50 x 10/49 x 9/48 = 0.0084 which is 118 to 1

Combined, i.e. hitting at least 2 is 0.1178 which is 7.5 to 1