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A quick and easy formula

  • 08-12-2006 5:25pm
    #1
    Registered Users, Registered Users 2 Posts: 1,151 ✭✭✭


    for two of your suit flopping can't seem to think of an easy way of formulating this as an equation and I am sure it is dead simple so anyone that can please do


Comments

  • Registered Users, Registered Users 2 Posts: 7,537 ✭✭✭Ste05


    Not sure about the formula for working it out, but it's 8.1/1, here's a link to all sorts of useful odds.

    http://www.planetstacked.com/holdem/odds/


  • Registered Users, Registered Users 2 Posts: 1,151 ✭✭✭Scouser in Dub


    Cheers thanks for that but if anyone has the workings out that would be appreciated also

    there's some really cool stuff there thanks Ste


  • Closed Accounts Posts: 3,362 ✭✭✭Hitman Actual


    for two of your suit flopping can't seem to think of an easy way of formulating this as an equation and I am sure it is dead simple so anyone that can please do

    Two in your hand?

    Prob = [(11C2)x(50-11)]/50C3
    =[((11x10)/(2*1))x39)/((50*49*48)/(3*2*1))]
    = 0.1094
    = ~8.1/1

    where 11C2 is the combination of flush cards left to flop in twos, which can be combined with the other 39 non-suited cards; 50C3 is the number of flop combinations not counting your two hole cards.


  • Registered Users, Registered Users 2 Posts: 347 ✭✭Brayruit


    An easier way (I think) to think it through...

    prob of exactly 2 of your suit hitting the flop (i.e. excluding probability of 3):

    prob first card is S = 11 / 50 (11 left in your suit from 50 unseen cards)
    prob 2nd card is S = 10 / 49
    prob 3rd card is NOT S = 39 / 48 (39 of remaining 48 cards are not your suit)

    This is probability of SSX. Also need SXS and XSS, so multiply answer by 3

    So the sum is 3 x 11/50 x 10/49 x 39/48 = 0.1094 which is 8.14 to 1

    If you want to add in the probability of SSS (i.e. all 3 in your suit) it is
    11/50 x 10/49 x 9/48 = 0.0084 which is 118 to 1

    Combined, i.e. hitting at least 2 is 0.1178 which is 7.5 to 1


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