VB6 find string at a given index

lukin

Is there a method in VB6 that will find a substring of a string given it's position in the string?
I know how to do it in VB.NET (below)


Dim StrText1 as String = ""
Dim StrText2 as String = ""
StrText1 ="Hello"
StrText2 = (strText1.Chars(1))

The above code would return "ello" to the variable StrText2.

Torak

Right()

lukin

Thanks Torak

FSL

Right(string, length) just gives the number of characters from the right specified by length. Mid(string, start[, length]) returns then number of characters specified by length, from string, starting at start. If length is not specified or is greater than the number of characters from start to the end of then it returns all the charaters from start to the end.

mountainyman

To return the substring use
Left$
Right$

dim strFilename as String
Dim strLastSlash as String
dim strDirectory as String

strLastSlash = InStrRev(strFilename, "\")
strDirectory = Left$(strFilename, strLastSlash)

MM