Advertisement
If you have a new account but are having problems posting or verifying your account, please email us on hello@boards.ie for help. Thanks :)
Hello all! Please ensure that you are posting a new thread or question in the appropriate forum. The Feedback forum is overwhelmed with questions that are having to be moved elsewhere. If you need help to verify your account contact hello@boards.ie
Hi there,
There is an issue with role permissions that is being worked on at the moment.
If you are having trouble with access or permissions on regional forums please post here to get access: https://www.boards.ie/discussion/2058365403/you-do-not-have-permission-for-that#latest

What's wrong with this C++ code (very small)

  • 02-03-2006 8:22pm
    #1
    Closed Accounts Posts: 1,299 ✭✭✭


    I want to calculate the total number of days present between a certain date and the year 1900.
    I have already allowed for leap years in my year_lenght function

    int totaldaysforyears (int year){

    int yearlength = 0;
    while (year!=1900){
    yearlength = yearlength + year_length(year);
    year--;
    }
    return yearlength;
    }


Comments

  • Closed Accounts Posts: 1,299 ✭✭✭Sandals


    I changed it to this, but no improvement, do I have to include Ampersants ? (&)?
    [SIZE="1"]#include <iostream>
    using namespace std;
    bool leap_year (int year);
    int month_length (int month,int year);
    int year_length (int year);
    int daysperyears(int year);
    int dayspermonths(int month);
    
    int main () {
    int month,year;
    cout << "Enter year " ;
    cin >> year;
    cout << "Enter month ";
    cin >> month;
    cout <<"Number of days in those years is " <<daysperyears (year)<<endl;
    
    cout <<month_length(month,year);
    system ("pause");
        return 0;
    }
    
    
    
    
    
    int month_length (int month, int year) {
      int m = month;
        if (m==2); 
          if (leap_year(year)) return 29;
            else 
            return 28;
        else if{ (m==9 || m==4 || m==6 || m==11)
             }
                return 30;
            else return 31;
    }
    
    
    bool leap_year (int year) {
         int y =year;
    //returns true if year is a leap year
        if (y % 4 == 0) //all others are definitely not leap
            if (y < 1583) return true;
            else //after 1583
                if ((y % 100 == 0) && (y % 400 != 0))
                    //e.g. 1900
                    return false;
                else //e.g. 1904 or 2000
                    return true;
        else //not divisible by 4
            return false;
    }
    
    int year_length (int year) {
        int y = year;
        if (leap_year (y)) 
            return 366;
         else return 365;
        }
        
        
        int daysperyears(int year){
        int y;
        int c=year;
            while (year>1900){
             y = y + year_length(year);
              c--;
              }
        
    return y;
       
    }
    
    int dayspermonths(int month){
        int y ;
        int m = month;
            while (m>0){
             y = y + month_length(m);
              m--;
              }
        
    return y;
       
    }
    [/SIZE]
    

    It says to few arguments to function int month_length?


  • Closed Accounts Posts: 4,943 ✭✭✭Mutant_Fruit


    put your code in [ CODE][ /CODE] tags and tell us exactly what the error is.


  • Closed Accounts Posts: 1,299 ✭✭✭Sandals


    done.


  • Registered Users, Registered Users 2 Posts: 1,481 ✭✭✭satchmo


    int month_length (int month,int year);
    y = y + month_length(m);
    It says to few arguments to function int month_length?
    ...


  • Closed Accounts Posts: 1,299 ✭✭✭Sandals


    Ok I am finished now but the final and ultimate calculation dayofyear(day,month,year)

    is continuosly coming back with the wrong value, can you see why?
    #include <iostream>
    using namespace std;
    
    
    bool leap_year (int year);
    int year_length (int year);
    int daysperyears(int year);
    int dayspermonths(int month,int year);
    int month_length (int month, int year);
    int dayofyear (int& day, int& month, int& year);
    int main () {
        int day, year,month;
    
    cout << "Enter year " ;
    cin >> year;
    cout << "Enter month ";
    cin >> month;
    cout << "Enter day ";
    cin >> day;
    cout <<"Number of days in those years is " <<daysperyears (year)<<endl;
    cout <<"Number of days in those months is " <<dayspermonths (month,year)<<endl;
    cout <<"days is "<<day<<endl;
    cout << "Total number of days is " << dayofyear ( day,  month,  year);
    
    system ("pause");
        return 0;
    }
    
    int daysperyears(int year){
        int y;
            while (year>1900){
             y = y + year_length(year);
              year--;
              }
        
    return y;
       
    }
    
    int year_length (int year) {
        if (leap_year (year)) 
            return 366;
         else return 365;
        }
        
    bool leap_year (int year) {
    //returns true if year is a leap year
        if (year % 4 == 0) //all others are definitely not leap
            if (year < 1583) return true;
            else //after 1583
                if ((year % 100 == 0) && (year % 400 != 0))
                    //e.g. 1900
                    return false;
                else //e.g. 1904 or 2000
                    return true;
        else //not divisible by 4
            return false;
    }
    
    
    
    
    
    
    int month_length (int month, int year) {
        if (month==2) 
          if (leap_year(year)) return 29;
            else return 28;
        else if (month==9 || month==4 || month==6 || month==11)
              
                return 30;
            else return 31;
    }
    
    
    int dayspermonths(int month,int year){
        int y;
            while (month>0){
             y = y + month_length(month,year);
              month--;
              }
        
    return y;
       
    }
    
    
    int dayofyear (int& day, int& month, int& year){
        
        int y;
        y = (day+ dayspermonths(month,year) + daysperyears(year));
    return y;
    }
    


  • Advertisement
  • Registered Users, Registered Users 2 Posts: 919 ✭✭✭timeout


    Surly you don't need the &? I mean you have not needed anywhere else in the code.


  • Closed Accounts Posts: 1,299 ✭✭✭Sandals


    I just put it in, i don't undertsand it, but it didn't seem to make a difference in or out!


  • Registered Users, Registered Users 2 Posts: 919 ✭✭✭timeout


    try seperating it out and printing out so you can see whats going on.
    int dayofyear (int day, int month, int year){
        
        int y,tempD,tempY;
        cout<<month <<" - "<<year;
        tempD = dayspermonths(month,year);
        cout<<"per month - " <<tempD;
        tempY = daysperyears(year);
        cout<<"per year - " <<tempY;
        y = (day+ tempM + tempY);
        cout<<"total - " <<y;
    
    return y;
    
    

    [Edit]Please note I don't have c compilier so have not tested your code or the above alteration


  • Closed Accounts Posts: 1,299 ✭✭✭Sandals


    ok the days and month calculate but the daysperyears function wont calculate inside the dayofyear function.


  • Registered Users, Registered Users 2 Posts: 919 ✭✭✭timeout


    But it does work the first time throught it? at this point
    cout <<"Number of days in those years is " <<daysperyears (year)<<endl;


  • Advertisement
  • Closed Accounts Posts: 1,299 ✭✭✭Sandals


    yes it definitely works there.

    Thanks for your help.


  • Registered Users, Registered Users 2 Posts: 919 ✭✭✭timeout


    And the year value is correct in the above altered code?
    I.E.
    2 - 1905
    per month - 52
    per year -
    Well stick in a bit of test code again to see the output:
    int daysperyears(int year){
        int y=0;
            while (year>1900){
              cout<<"in daysperyears - " <<year;
              y = y + year_length(year);
              cout<<"in daysperyears Y value - " <<y;
              year--;
              }
        
    return y;
    
    [edit] forgetting my ;


  • Closed Accounts Posts: 1,299 ✭✭✭Sandals


    Now I'm getting the following errors;
    91 C:\Documents and Settings\Administrator\My Documents\bobo\Untitled6.cpp call of overloaded `dayspermonths(int&, int&)' is ambiguous

    91 C:\Documents and Settings\Administrator\My Documents\bobo\Untitled6.cpp call of overloaded `dayspermonths(int&, int&)' is ambiguous

    91 C:\Documents and Settings\Administrator\My Documents\bobo\Untitled6.cpp call of overloaded `dayspermonths(int&, int&)' is ambiguous
    #include <iostream>
    using namespace std;
    
    
    bool leap_year (int year);
    int year_length (int year);
    int daysperyears(int year);
    int dayspermonths(int month,int year);
    int month_length (int month, int year);
    int dayofyear (int day, int month, int year);
    int main () {
        int day, month,year;
    
      cout << "Enter a date to be converted to a number:";
      cin >> day >>month>>year;
    
    
    
    cout <<"Number of days in those years is " <<daysperyears (year)<<endl;
    cout <<"Number of days in those months is " <<dayspermonths (month,year);
    cout << "Total number of days is " << dayofyear ( day,  month,  year);
    system ("pause");
        return 0;
    }
    
    
    int daysperyears(int year){
        int y=0;
            while (year>1900){
              cout<<"in daysperyears - " <<year;
              y = y + year_length(year);
              cout<<"in daysperyears Y value - " <<y;
              year--;
              }
        
    return y;
    }
    int year_length (int year) {
        if (leap_year (year)) 
            return 366;
         else return 365;
        }
        
    bool leap_year (int year) {
    //returns true if year is a leap year
        if (year % 4 == 0) //all others are definitely not leap
            if (year < 1583) return true;
            else //after 1583
                if ((year % 100 == 0) && (year % 400 != 0))
                    //e.g. 1900
                    return false;
                else //e.g. 1904 or 2000
                    return true;
        else //not divisible by 4
            return false;
    }
    
    
    
    
    
    
    int month_length (int month, int year) {
        if (month==2) 
          if (leap_year(year)) return 29;
            else return 28;
        else if (month==9 || month==4 || month==6 || month==11)
              
                return 30;
            else return 31;
    }
    
    
    int dayspermonths(int& month,int& year){
        int y;
            while (month>0){
             y = y + month_length(month,year);
              month--;
              }
        
    return y;
       
    }
    
    
    int dayofyear (int day, int month, int year){
        
        int y,tempD,tempY;
        cout<<month <<" - "<<year;
        tempD = dayspermonths(month,year);
        cout<< "per month - " <<tempD;
        tempY = daysperyears(year);
        cout<<"per year - " <<tempY;
        y = (day+ tempD + tempY);
        cout<<"total - " <<y;
    
    return y;
    
    }
    


  • Registered Users, Registered Users 2 Posts: 18 suavek


    you get those errors because you have declared two different functions sharing the same name: int dayofyear (int day, int month, int year) and int dayofyear (int& day, int& month, int& year). I mean that's the way your compiler sees things.

    [EDIT] Shame on me, I pasted the wrong fragment of code :p It's the dayspermonths function. Timeout got it right.


  • Closed Accounts Posts: 1,299 ✭✭✭Sandals


    I don't quiet get you, which one should I change?


  • Registered Users, Registered Users 2 Posts: 919 ✭✭✭timeout


    Its the dayspermonth, you brought back in the &. There is no need for it so leave it out.

    [edit]i download and installed a compiler and that code runs fine with the & removed,also added <<endl for readability, man this brings back memories :D What dates you giving it?


  • Closed Accounts Posts: 1,299 ✭✭✭Sandals


    Ok cool thank you all so much i have it now, ji also had to change a bit in the month length function to make it >1 rather than 0.


Advertisement