This program I have to do

Sandals

so this is the c++ program I have to make

Sample interaction (but don’t feel totally constrained by this):
Enter a company code, and number of shares held: BOI 100
Enter the day month and year of purchase of these shares: 3 7 2005
100 BOI purchased for £2015.00, today worth £2022.00, gain of 3.47%
Do you have more shares? Y
Enter a company code, and number of shares held: FFA 350
Enter the day month and year of purchase of these shares: 22 11 1999
350 FFA purchased for £7112.00, today worth £7077.00, loss of 0.5%
Do you have more shares? N
Total purchase price was £9127.00.
Current value is £9099.00.
Loss since purchase of £28.00 or 0.3% of £9127.00

And I have until where theyask ou "Do you have more shares" bit,
how do i set it up to recognise the y for yes or n for no if you get me

I need to do a while loop that will keep looping while the value is y(as in yes),
but how do I set that up?
is it some kind of character as in while (x==n),

I'm sure it's easy but I cant figure it out.

Karoma

You didn't even specify which language... gah!


Read in a Char from the keyboard...
Look up "loops" do While or if or.. there's a dozen ways to do it


Is it that you don't know how to read input from a keyboard? Or that you don't know about different types? Or that you don't know loops?
What year are you in ?
oO

Sandals

sorry that was stupid of me it's c++

Smellyirishman

My C++ is none existant so bear with me.

Very simplistically your looking at

char input = 'y'

while( input == 'y' || input == 'Y')
read in shares
std::cout << "Do you have more"
std::cin >> input

finish up

Sandals

THESE THREE LINES ARE NOT WORKING;

cout << "Do You have more shares (y/n)?";
cin >> x;
while (x == "y"){

BrokenArrows

they should work. Its perfect code. lol

Anyway what do you mean by not working?
Not doing what you want?
Not compiling?

Smellyirishman

You cannot test equivilance on Strings using ==, you must use a function.
I think the function in C++ is Compare(String A, String B, bool ignoreCase). This function returns a float depending on whether the string is "lesser" ( returns < 0 I think) or "greater" ( > 0), if they are equal then 0 is returned.

So in order to check if the char entered ( x in your case ) is equal to 'y' then you must use the single character quotes. IE;

while ( x == 'y' )

using a string it would be

while ( Compare(x,"y",true) == 0 )

Did you import the libraries for IO? Try using std::cin and std::cout instead.

Again, take this with a pinch of salt.

Sandals

I dont know how to import the libraries for Io,
what should I call x,
is it an int or a char
like
int x;
or char x[2];

? thanks for your help.

Sandals

This is what I have, and some where here the problem lies, the rest of program works fine;

char companycode[80],t[80];
int number_shares,day,month,year,pday,pmonth,pyear;
cout << "Do You have more shares (y/n)?";
cin >> t;


while ( t == 'y' ){

Smellyirishman

K, well I don't want to give too much away...

Here is the entire, 100% working code to do a while loop reading in "shares" until the user enters something other than y.
It's very basic and straight forward, if your stuck on any of it say so.

#include  <iostream>

using std::cout;
using std::cin;
using std::endl;

int main()
{
    int share = 0;
    char input = 'y';
    
    while( 'y' == input ) 
    { 
           cout << "Please enter new share value  ";
           cin >> share;
           cout << endl;
           cout << "Valude entered was : " << share;
           cout << endl;
           cout << "Do you want to enter more shares?";
           cin >> input;
    }
    
    return 0;
}