TheBody wrote: » If it's the way I suggest, it's just regular substitution. Let [latex]u=6x^2-5x+3[/latex].
TheBody wrote: » You asked this problem before. At the time, I suggested, based on the level of questions I have seen you post in the past, that this may be a typo. I think it may be upside down. I think they may have wanted: [latex]\int\frac{12x-5}{6x^2-5x+3}dx[/latex]. Perhaps you can clarify this with your lecturer?
Hedgecutter wrote: » On the home run now, exams in june. Thermodynamics taking up a huge amount of time.
TheBody wrote: » How's the course going this term?
TheBody wrote: » I presume you are asked to differentiate both? If so, they look good to me. The only suggestion I would make is to tidy up the last lines in each problem. Well done!
Hedgecutter wrote: » Two past paper questions i'am attempting. Am I using the right rules?
TheBody wrote: » Time for bed but keep the questions coming and I'll get back to you on them as soon as I can.
TheBody wrote: » The problem I have with khans videos is that by the time he is finished, the screen is a mess of scribbles and stuff all over the place.
Hedgecutter wrote: » Ya sometimes I find Khan methods slightly different to the way I'm being taught.
TheBody wrote: » Personally, I think it's better than khan academy (https://www.khanacademy.org/) which you may know about already. Use the search function if you can't spot the topic you are looking for.
Hedgecutter wrote: » Cheers. Look very good. Looks to have a hell of a lot of information there.
TheBody wrote: » You might like this website.http://patrickjmt.com/ Scroll down the page to the calculus section. REALLY good videos on everything you need to know!!
TheBody wrote: » So I got a pen and paper to do this problem and it's a lot harder than it looks. I initially thought it was substitution. Based on the standard of problem you have shown me so far, I am wondering if it is an error. I think they probably wanted to have: [latex]\int \frac{12x-5}{6x^2-5x+3}[/latex]. This would be much more in keeping with the style of problem you have been doing so far.
TheBody wrote: » No, it's not partial fractions. DIFFERENTIATE the top line and see if you notice anything......
Hedgecutter wrote: » do we use partial fractions method. factorise the top line? but you can only factorise the denominator
TheBody wrote: » When it comes to deciding if an integral is to be done using regular substitution, you ask yourself, is there anything there that if DIFFERENTIATED, would give you the other bit, and your not too bothered about constants? You have to deal with any constants but they don't cause any trouble. If there is, then you let that bit be "u". So, With that in mind and looking at your problem, do you notice anything between the top and bottom?
Hedgecutter wrote: » What method do I use for part (1)
Hedgecutter wrote: » The equivalent of second year. If I pass this year I'll have a level 6 higher certificate.